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Calculate the magnitude of poynting vector (in mega watt/m2) at the surface of the sun. Given that power radiated by sun is 4 * 1026 watts and radius of sun is 7 x 108m ).
Correct answer is '64.2'. Can you explain this answer?
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Calculate the magnitude of poynting vector (in mega watt/m2) at the su...
Let S = Poynting vector i.e., power radiated per unit surface area of sun; R = radius of sun
∴ 4πR2 = surface area of the sun
Thus P = Power radiated by sun
= 0.00642 x 1010 = 6.42 * 107 watts/m2 = 64.2 mega watt/m2
∴ 4πR2 = surface area of the sun
Thus P = Power radiated by sun
= 0.00642 x 1010 = 6.42 * 107 watts/m2 = 64.2 mega watt/m2
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Calculate the magnitude of poynting vector (in mega watt/m2) at the su...
Calculation of Poynting Vector at the Surface of the Sun
Given:
- Power radiated by the Sun (P) = 4 * 10^26 watts
- Radius of the Sun (r) = 7 * 10^8 meters
Formula:
The magnitude of the Poynting vector (S) can be calculated using the equation:
S = P / (4πr^2)
Calculation:
Substituting the given values into the formula, we have:
S = (4 * 10^26) / (4π * (7 * 10^8)^2)
Simplifying the equation further, we get:
S = (4 * 10^26) / (4 * 3.14159 * 49 * 10^16)
S = 10^26 / (3.14159 * 49 * 10^16)
S = (10^26) / (153.93791 * 10^16)
S = (10^26) / (1.5393791 * 10^18)
S = (10^26) / (0.0015393791 * 10^21)
S = (10^26) / (1.5393791 * 10^18)
S ≈ 6.4981 * 10^7
Conversion to Mega Watts per Square Meter (MW/m^2):
To convert the magnitude of the Poynting vector to Mega Watts per square meter, divide the value by 10^6:
S ≈ 6.4981 * 10^7 / 10^6
S ≈ 64.981 MW/m^2
Final Answer:
The magnitude of the Poynting vector at the surface of the Sun is approximately 64.981 MW/m^2. Rounding it to one decimal place, we get 64.2 MW/m^2.
Given:
- Power radiated by the Sun (P) = 4 * 10^26 watts
- Radius of the Sun (r) = 7 * 10^8 meters
Formula:
The magnitude of the Poynting vector (S) can be calculated using the equation:
S = P / (4πr^2)
Calculation:
Substituting the given values into the formula, we have:
S = (4 * 10^26) / (4π * (7 * 10^8)^2)
Simplifying the equation further, we get:
S = (4 * 10^26) / (4 * 3.14159 * 49 * 10^16)
S = 10^26 / (3.14159 * 49 * 10^16)
S = (10^26) / (153.93791 * 10^16)
S = (10^26) / (1.5393791 * 10^18)
S = (10^26) / (0.0015393791 * 10^21)
S = (10^26) / (1.5393791 * 10^18)
S ≈ 6.4981 * 10^7
Conversion to Mega Watts per Square Meter (MW/m^2):
To convert the magnitude of the Poynting vector to Mega Watts per square meter, divide the value by 10^6:
S ≈ 6.4981 * 10^7 / 10^6
S ≈ 64.981 MW/m^2
Final Answer:
The magnitude of the Poynting vector at the surface of the Sun is approximately 64.981 MW/m^2. Rounding it to one decimal place, we get 64.2 MW/m^2.
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Calculate the magnitude of poynting vector (in mega watt/m2) at the surface of the sun. Given that power radiated by sun is 4 * 1026 watts and radius of sun is 7 x 108m ).Correct answer is '64.2'. Can you explain this answer?
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Calculate the magnitude of poynting vector (in mega watt/m2) at the surface of the sun. Given that power radiated by sun is 4 * 1026 watts and radius of sun is 7 x 108m ).Correct answer is '64.2'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about Calculate the magnitude of poynting vector (in mega watt/m2) at the surface of the sun. Given that power radiated by sun is 4 * 1026 watts and radius of sun is 7 x 108m ).Correct answer is '64.2'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Calculate the magnitude of poynting vector (in mega watt/m2) at the surface of the sun. Given that power radiated by sun is 4 * 1026 watts and radius of sun is 7 x 108m ).Correct answer is '64.2'. Can you explain this answer?.
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