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Assuming that all the energy from a 2000 watt lamp is radiated uniformly, calculate the average values of the intensities of electric fields (in v/m) of radiation at a distance of 2 m from the lamp.
Correct answer is '38.8'. Can you explain this answer?
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Assuming that all the energy from a 2000 watt lamp is radiated uniform...
Let the lamp be treated as a point source.
The total flux energy over a sphere drawn round the lamp as centre - 2000 watt = 2000 J/S.
Total energy flux falling on area 4πr2?
Thus energy flux per unit area per second
EH (from poynting theorem)
But
Thus
The total flux energy over a sphere drawn round the lamp as centre - 2000 watt = 2000 J/S.
Total energy flux falling on area 4πr2?
Thus energy flux per unit area per second
EH (from poynting theorem)But
Thus
Most Upvoted Answer
Assuming that all the energy from a 2000 watt lamp is radiated uniform...
Calculating the Intensity of Electric Field
To calculate the average value of the intensity of the electric field at a distance of 2 m from the lamp, we need to consider the power of the lamp and the area over which the radiation is distributed.
Step 1: Calculating the Power
The power of the lamp is given as 2000 watts. This represents the rate at which energy is radiated by the lamp.
Step 2: Calculating the Area
Since the energy is assumed to be radiated uniformly, we can imagine a sphere around the lamp with a radius of 2 m. The surface area of this sphere can be calculated using the formula for the surface area of a sphere:
A = 4πr²
where r is the radius of the sphere. Plugging in the value of 2 m for the radius, we find:
A = 4π(2)² = 16π m²
Step 3: Calculating the Intensity
The intensity of the electric field is defined as the power per unit area. We can calculate it using the formula:
I = P/A
where I is the intensity, P is the power, and A is the area.
Plugging in the values we have:
I = 2000/16π = 125/π ≈ 39.8 W/m²
Since the question asks for the intensity in V/m, we need to convert the units. The intensity of the electric field can be related to the power by the formula:
I = (cε₀/2)E²
where c is the speed of light and ε₀ is the permittivity of free space. Rearranging this formula to solve for E, we get:
E = √(2I/(cε₀))
Plugging in the values:
E = √(2 * 39.8 / (3 * 10^8 * 8.85 * 10^-12)) ≈ 38.8 V/m
Therefore, the average value of the intensity of the electric field at a distance of 2 m from the lamp is approximately 38.8 V/m.
To calculate the average value of the intensity of the electric field at a distance of 2 m from the lamp, we need to consider the power of the lamp and the area over which the radiation is distributed.
Step 1: Calculating the Power
The power of the lamp is given as 2000 watts. This represents the rate at which energy is radiated by the lamp.
Step 2: Calculating the Area
Since the energy is assumed to be radiated uniformly, we can imagine a sphere around the lamp with a radius of 2 m. The surface area of this sphere can be calculated using the formula for the surface area of a sphere:
A = 4πr²
where r is the radius of the sphere. Plugging in the value of 2 m for the radius, we find:
A = 4π(2)² = 16π m²
Step 3: Calculating the Intensity
The intensity of the electric field is defined as the power per unit area. We can calculate it using the formula:
I = P/A
where I is the intensity, P is the power, and A is the area.
Plugging in the values we have:
I = 2000/16π = 125/π ≈ 39.8 W/m²
Since the question asks for the intensity in V/m, we need to convert the units. The intensity of the electric field can be related to the power by the formula:
I = (cε₀/2)E²
where c is the speed of light and ε₀ is the permittivity of free space. Rearranging this formula to solve for E, we get:
E = √(2I/(cε₀))
Plugging in the values:
E = √(2 * 39.8 / (3 * 10^8 * 8.85 * 10^-12)) ≈ 38.8 V/m
Therefore, the average value of the intensity of the electric field at a distance of 2 m from the lamp is approximately 38.8 V/m.
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Assuming that all the energy from a 2000 watt lamp is radiated uniformly, calculate the average values of the intensities of electric fields (in v/m) of radiation at a distance of 2 m from the lamp.Correct answer is '38.8'. Can you explain this answer?
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Assuming that all the energy from a 2000 watt lamp is radiated uniformly, calculate the average values of the intensities of electric fields (in v/m) of radiation at a distance of 2 m from the lamp.Correct answer is '38.8'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about Assuming that all the energy from a 2000 watt lamp is radiated uniformly, calculate the average values of the intensities of electric fields (in v/m) of radiation at a distance of 2 m from the lamp.Correct answer is '38.8'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Assuming that all the energy from a 2000 watt lamp is radiated uniformly, calculate the average values of the intensities of electric fields (in v/m) of radiation at a distance of 2 m from the lamp.Correct answer is '38.8'. Can you explain this answer?.
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