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Two point charges q1 = - 2 C and q2 = - 1 C are separa ted by a distance d. The position on the line joining the two charges where a third charge q = + 1C will be in equilibrium is at a distance
  • a)
    d/√2 from q1, between q1 and q2
  • b)
    d/√2 from q1 away from q2
  • c)
     from q2, between q1 and q2
  • d)
    from q2 away from q1 
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Two point charges q1 = - 2 C and q2 = - 1 C are separa ted by a distan...
When two charges are of same nature (both positive or both negative) then neutral point is always between the two charges on the line joining them. But when two charges are of opposite nature (one positive and other negative) then neutral point is always outside the two charges on the extended line joining the two charges.
So. we conclude that options (A) and (C) are absolutely ruled out.

 
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Most Upvoted Answer
Two point charges q1 = - 2 C and q2 = - 1 C are separa ted by a distan...
When two charges are of same nature (both positive or both negative) then neutral point is always between the two charges on the line joining them. But when two charges are of opposite nature (one positive and other negative) then neutral point is always outside the two charges on the extended line joining the two charges.
So. we conclude that options (A) and (C) are absolutely ruled out.

 
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Two point charges q1 = - 2 C and q2 = - 1 C are separa ted by a distance d. The position on the line joining the two charges where a third charge q = + 1C will be in equilibrium is at a distancea)d/√2 from q1, between q1 and q2b)d/√2from q1 away from q2c)from q2, between q1 and q2d)from q2 away from q1Correct answer is option 'C'. Can you explain this answer?
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