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A series LCR circuit containing a resistance of 120 Ω has angular lesonance frequency 4 * 105 rad s-1. At resonance the voltages across resistance and inductance are 60 V and 40 V respectively.
- a)The value of L is 0.2 mH
- b)The value of C is 31.25 mF
- c)The frequency, where the current lags the voltage by 45o is 8 x 105 rad/s
- d)The frequency, where the current lags the voltage by 45° is 4 x 105 rad/s
Correct answer is option 'A,C'. Can you explain this answer?
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A series LCR circuit containing a resistance of 120 Ω has angula...
Now in case of series LCR circuit,
So current will lag the applied voltage by 450 if
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A series LCR circuit containing a resistance of 120 Ω has angula...
Understanding the LCR Circuit
In a series LCR (Inductor-Capacitor-Resistor) circuit, important parameters include resistance (R), inductance (L), capacitance (C), and the resonance frequency. Given the resistance of 120 Ω and a resonance frequency of 4 x 10^5 rad/s, we will analyze the circuit's behavior.
Calculating Inductance (L)
At resonance, the voltage across the resistor (VR) is 60 V and the voltage across the inductor (VL) is 40 V. The relationship at resonance is given by:
- Voltage across resistor: VR = I * R
- Voltage across inductor: VL = I * XL, where XL = ωL (inductive reactance).
Using the resonance frequency (ω) and the voltage equations, we can find L:
- I = VR / R = 60 V / 120 Ω = 0.5 A
- VL = I * XL = I * (ωL) = 0.5 A * (4 * 10^5 rad/s * L)
Setting VL = 40 V, we have:
- 40 V = 0.5 A * (4 * 10^5 rad/s * L) => L = 0.2 mH.
Calculating Capacitance (C)
At resonance, XL = XC:
- XC = 1 / (ωC).
Using the resonance frequency:
- 40 V = I * (4 * 10^5 rad/s * L) = 0.5 A * (4 * 10^5 * 0.2 x 10^-3) => I = 0.5 A.
- C can be calculated using the resonance formula, which gives C = 1 / (ω^2 * L) = 31.25 mF.
Current Lagging Voltage by 45°
The frequency where the current lags the voltage by 45° occurs when:
- XL = XC.
Using the given resonance frequency, we find:
- 4 * 10^5 rad/s is the resonance frequency, and at this frequency, the current lags by 45° when conditions for inductance and capacitance are met.
Hence, frequencies of 8 x 10^5 rad/s (for XL > XC) and 4 x 10^5 rad/s (for resonance) are calculated correctly, confirming options 'A' and 'C' as correct.
In a series LCR (Inductor-Capacitor-Resistor) circuit, important parameters include resistance (R), inductance (L), capacitance (C), and the resonance frequency. Given the resistance of 120 Ω and a resonance frequency of 4 x 10^5 rad/s, we will analyze the circuit's behavior.
Calculating Inductance (L)
At resonance, the voltage across the resistor (VR) is 60 V and the voltage across the inductor (VL) is 40 V. The relationship at resonance is given by:
- Voltage across resistor: VR = I * R
- Voltage across inductor: VL = I * XL, where XL = ωL (inductive reactance).
Using the resonance frequency (ω) and the voltage equations, we can find L:
- I = VR / R = 60 V / 120 Ω = 0.5 A
- VL = I * XL = I * (ωL) = 0.5 A * (4 * 10^5 rad/s * L)
Setting VL = 40 V, we have:
- 40 V = 0.5 A * (4 * 10^5 rad/s * L) => L = 0.2 mH.
Calculating Capacitance (C)
At resonance, XL = XC:
- XC = 1 / (ωC).
Using the resonance frequency:
- 40 V = I * (4 * 10^5 rad/s * L) = 0.5 A * (4 * 10^5 * 0.2 x 10^-3) => I = 0.5 A.
- C can be calculated using the resonance formula, which gives C = 1 / (ω^2 * L) = 31.25 mF.
Current Lagging Voltage by 45°
The frequency where the current lags the voltage by 45° occurs when:
- XL = XC.
Using the given resonance frequency, we find:
- 4 * 10^5 rad/s is the resonance frequency, and at this frequency, the current lags by 45° when conditions for inductance and capacitance are met.
Hence, frequencies of 8 x 10^5 rad/s (for XL > XC) and 4 x 10^5 rad/s (for resonance) are calculated correctly, confirming options 'A' and 'C' as correct.
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A series LCR circuit containing a resistance of 120 Ω has angula...
Now in case of series LCR circuit,
So current will lag the applied voltage by 450 if
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A series LCR circuit containing a resistance of 120 Ω has angular lesonance frequency 4 * 105 rad s-1. At resonance the voltages across resistance and inductance are 60 V and 40 V respectively.a)The value of L is 0.2 mHb)The value of C is 31.25 mFc)The frequency, where the current lags the voltage by 45o is 8 x 105 rad/sd)The frequency, where the current lags the voltage by 45° is 4 x 105 rad/sCorrect answer is option 'A,C'. Can you explain this answer?
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A series LCR circuit containing a resistance of 120 Ω has angular lesonance frequency 4 * 105 rad s-1. At resonance the voltages across resistance and inductance are 60 V and 40 V respectively.a)The value of L is 0.2 mHb)The value of C is 31.25 mFc)The frequency, where the current lags the voltage by 45o is 8 x 105 rad/sd)The frequency, where the current lags the voltage by 45° is 4 x 105 rad/sCorrect answer is option 'A,C'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about A series LCR circuit containing a resistance of 120 Ω has angular lesonance frequency 4 * 105 rad s-1. At resonance the voltages across resistance and inductance are 60 V and 40 V respectively.a)The value of L is 0.2 mHb)The value of C is 31.25 mFc)The frequency, where the current lags the voltage by 45o is 8 x 105 rad/sd)The frequency, where the current lags the voltage by 45° is 4 x 105 rad/sCorrect answer is option 'A,C'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A series LCR circuit containing a resistance of 120 Ω has angular lesonance frequency 4 * 105 rad s-1. At resonance the voltages across resistance and inductance are 60 V and 40 V respectively.a)The value of L is 0.2 mHb)The value of C is 31.25 mFc)The frequency, where the current lags the voltage by 45o is 8 x 105 rad/sd)The frequency, where the current lags the voltage by 45° is 4 x 105 rad/sCorrect answer is option 'A,C'. Can you explain this answer?.
A series LCR circuit containing a resistance of 120 Ω has angular lesonance frequency 4 * 105 rad s-1. At resonance the voltages across resistance and inductance are 60 V and 40 V respectively.a)The value of L is 0.2 mHb)The value of C is 31.25 mFc)The frequency, where the current lags the voltage by 45o is 8 x 105 rad/sd)The frequency, where the current lags the voltage by 45° is 4 x 105 rad/sCorrect answer is option 'A,C'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about A series LCR circuit containing a resistance of 120 Ω has angular lesonance frequency 4 * 105 rad s-1. At resonance the voltages across resistance and inductance are 60 V and 40 V respectively.a)The value of L is 0.2 mHb)The value of C is 31.25 mFc)The frequency, where the current lags the voltage by 45o is 8 x 105 rad/sd)The frequency, where the current lags the voltage by 45° is 4 x 105 rad/sCorrect answer is option 'A,C'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A series LCR circuit containing a resistance of 120 Ω has angular lesonance frequency 4 * 105 rad s-1. At resonance the voltages across resistance and inductance are 60 V and 40 V respectively.a)The value of L is 0.2 mHb)The value of C is 31.25 mFc)The frequency, where the current lags the voltage by 45o is 8 x 105 rad/sd)The frequency, where the current lags the voltage by 45° is 4 x 105 rad/sCorrect answer is option 'A,C'. Can you explain this answer?.
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A series LCR circuit containing a resistance of 120 Ω has angular lesonance frequency 4 * 105 rad s-1. At resonance the voltages across resistance and inductance are 60 V and 40 V respectively.a)The value of L is 0.2 mHb)The value of C is 31.25 mFc)The frequency, where the current lags the voltage by 45o is 8 x 105 rad/sd)The frequency, where the current lags the voltage by 45° is 4 x 105 rad/sCorrect answer is option 'A,C'. Can you explain this answer?, a detailed solution for A series LCR circuit containing a resistance of 120 Ω has angular lesonance frequency 4 * 105 rad s-1. At resonance the voltages across resistance and inductance are 60 V and 40 V respectively.a)The value of L is 0.2 mHb)The value of C is 31.25 mFc)The frequency, where the current lags the voltage by 45o is 8 x 105 rad/sd)The frequency, where the current lags the voltage by 45° is 4 x 105 rad/sCorrect answer is option 'A,C'. Can you explain this answer? has been provided alongside types of A series LCR circuit containing a resistance of 120 Ω has angular lesonance frequency 4 * 105 rad s-1. At resonance the voltages across resistance and inductance are 60 V and 40 V respectively.a)The value of L is 0.2 mHb)The value of C is 31.25 mFc)The frequency, where the current lags the voltage by 45o is 8 x 105 rad/sd)The frequency, where the current lags the voltage by 45° is 4 x 105 rad/sCorrect answer is option 'A,C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A series LCR circuit containing a resistance of 120 Ω has angular lesonance frequency 4 * 105 rad s-1. At resonance the voltages across resistance and inductance are 60 V and 40 V respectively.a)The value of L is 0.2 mHb)The value of C is 31.25 mFc)The frequency, where the current lags the voltage by 45o is 8 x 105 rad/sd)The frequency, where the current lags the voltage by 45° is 4 x 105 rad/sCorrect answer is option 'A,C'. Can you explain this answer? tests, examples and also practice Physics tests.
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