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Two particles of mass 1kg and 0.5kg are moving in the same direction with speed of 2 m/s and 6 m/s respectively on a smooth horizontal surface. The speed of centre of mass of the system in m/s is :
Correct answer is '3.333'. Can you explain this answer?
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Two particles of mass 1kgand 0.5kgare moving in the same direction wit...
The correct answer is: 3.333
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Two particles of mass 1kgand 0.5kgare moving in the same direction wit...
The speed of the center of mass of a system can be calculated using the formula:
Vcm = (m1v1 + m2v2) / (m1 + m2)
where Vcm is the speed of the center of mass, m1 and m2 are the masses of the particles, and v1 and v2 are their respective speeds.
Given:
Mass of particle 1 (m1) = 1 kg
Mass of particle 2 (m2) = 0.5 kg
Speed of particle 1 (v1) = 2 m/s
Speed of particle 2 (v2) = 6 m/s
Let's calculate the speed of the center of mass using the given values:
Vcm = (m1v1 + m2v2) / (m1 + m2)
Vcm = (1 kg * 2 m/s + 0.5 kg * 6 m/s) / (1 kg + 0.5 kg)
Vcm = (2 kg m/s + 3 kg m/s) / 1.5 kg
Vcm = 5 kg m/s / 1.5 kg
Vcm = 3.333 m/s
Therefore, the speed of the center of mass of the system is 3.333 m/s.
Explanation:
The center of mass is a point that represents the average position of the mass distribution in a system. It is a useful concept in physics as it simplifies the analysis of the motion of a system of particles.
In this scenario, we have two particles of different masses moving in the same direction. The center of mass of the system will move in the same direction as the particles but at a different speed. The speed of the center of mass is determined by the masses of the particles and their respective speeds.
Using the formula for the speed of the center of mass, we can calculate the result. By plugging in the given values, we find that the speed of the center of mass is 3.333 m/s.
This means that the center of mass of the system is moving at an average speed of 3.333 m/s. It is important to note that the center of mass does not necessarily coincide with the position of any of the particles. It represents the overall motion of the system as a whole.
Vcm = (m1v1 + m2v2) / (m1 + m2)
where Vcm is the speed of the center of mass, m1 and m2 are the masses of the particles, and v1 and v2 are their respective speeds.
Given:
Mass of particle 1 (m1) = 1 kg
Mass of particle 2 (m2) = 0.5 kg
Speed of particle 1 (v1) = 2 m/s
Speed of particle 2 (v2) = 6 m/s
Let's calculate the speed of the center of mass using the given values:
Vcm = (m1v1 + m2v2) / (m1 + m2)
Vcm = (1 kg * 2 m/s + 0.5 kg * 6 m/s) / (1 kg + 0.5 kg)
Vcm = (2 kg m/s + 3 kg m/s) / 1.5 kg
Vcm = 5 kg m/s / 1.5 kg
Vcm = 3.333 m/s
Therefore, the speed of the center of mass of the system is 3.333 m/s.
Explanation:
The center of mass is a point that represents the average position of the mass distribution in a system. It is a useful concept in physics as it simplifies the analysis of the motion of a system of particles.
In this scenario, we have two particles of different masses moving in the same direction. The center of mass of the system will move in the same direction as the particles but at a different speed. The speed of the center of mass is determined by the masses of the particles and their respective speeds.
Using the formula for the speed of the center of mass, we can calculate the result. By plugging in the given values, we find that the speed of the center of mass is 3.333 m/s.
This means that the center of mass of the system is moving at an average speed of 3.333 m/s. It is important to note that the center of mass does not necessarily coincide with the position of any of the particles. It represents the overall motion of the system as a whole.
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Community Answer
Two particles of mass 1kgand 0.5kgare moving in the same direction wit...
C. m=M1 V1 + M2 V2 / M1+M2
c. m=1*2 + 0.5*6 /1+0.5
c. m=2+3 /1.5
c. m=5/1.5 =3.333
c. m=1*2 + 0.5*6 /1+0.5
c. m=2+3 /1.5
c. m=5/1.5 =3.333
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