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The spherical surface of a plane -convex lens of radius of curvature R = 2m is gently placed on a flat plate. The space between them is filled with a transparent liquid of refractive index 1.5. The refractive indices of the lens and the flat are 1.4 and 1.6 respectively. The radius of the fifteen dark newton's ring in the reflected light of wavelength λ is found to be √5m.m. Determine the wave length λ (in microns) of the light.
Correct answer is '0.25'. Can you explain this answer?
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Verified Answer
The spherical surface of a plane -convex lens of radius of curvature R...
We know for minima in newtons ring
where n=1. 2. 3
(a) for n = 15
e = thickness of liquid film = x2/2R
X = radius of ring
R = radius of curvature of lens one gets
Given μ = 1.5
R = 2m
n = 15
So,
So. λ = 0.25 * 10-6 m
where n=1. 2. 3
(a) for n = 15
e = thickness of liquid film = x2/2R
X = radius of ring
R = radius of curvature of lens one gets
Given μ = 1.5
R = 2m
n = 15
So,
So. λ = 0.25 * 10-6 m
Most Upvoted Answer
The spherical surface of a plane -convex lens of radius of curvature R...
We know for minima in newtons ring
where n=1. 2. 3
(a) for n = 15
e = thickness of liquid film = x2/2R
X = radius of ring
R = radius of curvature of lens one gets
Given μ = 1.5
R = 2m
n = 15
So,
So. λ = 0.25 * 10-6 m
where n=1. 2. 3
(a) for n = 15
e = thickness of liquid film = x2/2R
X = radius of ring
R = radius of curvature of lens one gets
Given μ = 1.5
R = 2m
n = 15
So,
So. λ = 0.25 * 10-6 m
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Community Answer
The spherical surface of a plane -convex lens of radius of curvature R...
To find the radius of the fifteenth dark Newton's ring, we can use the formula:
r = sqrt(n * λ * R)
Where:
r = radius of the Newton's ring
n = order of the ring (in this case, 15)
λ = wavelength of the light
R = radius of curvature of the lens
First, let's find the wavelength of the reflected light. We know that the refractive index of the flat plate is 1.6, so the speed of light in the flat plate will be:
v = c / n
Where:
v = speed of light in the flat plate
c = speed of light in vacuum
n = refractive index of the flat plate
Using the given refractive index of the flat plate (1.6), we can calculate the speed of light in the flat plate:
v = c / 1.6
Next, let's find the wavelength of the reflected light using the formula:
λ = v / f
Where:
λ = wavelength of the reflected light
v = speed of light in the flat plate
f = frequency of the light
The frequency of the light remains constant, so we can use the same frequency as the incident light. Let's say the frequency is f.
Now, we can substitute the values into the formula for the radius of the fifteenth dark Newton's ring:
r = sqrt(n * λ * R)
Substituting the values we have calculated, we can find the radius of the fifteenth dark Newton's ring.
r = sqrt(n * λ * R)
Where:
r = radius of the Newton's ring
n = order of the ring (in this case, 15)
λ = wavelength of the light
R = radius of curvature of the lens
First, let's find the wavelength of the reflected light. We know that the refractive index of the flat plate is 1.6, so the speed of light in the flat plate will be:
v = c / n
Where:
v = speed of light in the flat plate
c = speed of light in vacuum
n = refractive index of the flat plate
Using the given refractive index of the flat plate (1.6), we can calculate the speed of light in the flat plate:
v = c / 1.6
Next, let's find the wavelength of the reflected light using the formula:
λ = v / f
Where:
λ = wavelength of the reflected light
v = speed of light in the flat plate
f = frequency of the light
The frequency of the light remains constant, so we can use the same frequency as the incident light. Let's say the frequency is f.
Now, we can substitute the values into the formula for the radius of the fifteenth dark Newton's ring:
r = sqrt(n * λ * R)
Substituting the values we have calculated, we can find the radius of the fifteenth dark Newton's ring.
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The spherical surface of a plane -convex lens of radius of curvature R = 2m is gently placed on a flat plate. The space between them is filled with a transparent liquid of refractive index 1.5. The refractive indices of the lens and the flat are 1.4 and 1.6 respectively. The radius of the fifteen dark newtons ring in the reflected light of wavelength λ is found to be √5m.m. Determine the wave length λ (in microns) of the light.Correct answer is '0.25'. Can you explain this answer?
Question Description
The spherical surface of a plane -convex lens of radius of curvature R = 2m is gently placed on a flat plate. The space between them is filled with a transparent liquid of refractive index 1.5. The refractive indices of the lens and the flat are 1.4 and 1.6 respectively. The radius of the fifteen dark newtons ring in the reflected light of wavelength λ is found to be √5m.m. Determine the wave length λ (in microns) of the light.Correct answer is '0.25'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about The spherical surface of a plane -convex lens of radius of curvature R = 2m is gently placed on a flat plate. The space between them is filled with a transparent liquid of refractive index 1.5. The refractive indices of the lens and the flat are 1.4 and 1.6 respectively. The radius of the fifteen dark newtons ring in the reflected light of wavelength λ is found to be √5m.m. Determine the wave length λ (in microns) of the light.Correct answer is '0.25'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The spherical surface of a plane -convex lens of radius of curvature R = 2m is gently placed on a flat plate. The space between them is filled with a transparent liquid of refractive index 1.5. The refractive indices of the lens and the flat are 1.4 and 1.6 respectively. The radius of the fifteen dark newtons ring in the reflected light of wavelength λ is found to be √5m.m. Determine the wave length λ (in microns) of the light.Correct answer is '0.25'. Can you explain this answer?.
The spherical surface of a plane -convex lens of radius of curvature R = 2m is gently placed on a flat plate. The space between them is filled with a transparent liquid of refractive index 1.5. The refractive indices of the lens and the flat are 1.4 and 1.6 respectively. The radius of the fifteen dark newtons ring in the reflected light of wavelength λ is found to be √5m.m. Determine the wave length λ (in microns) of the light.Correct answer is '0.25'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about The spherical surface of a plane -convex lens of radius of curvature R = 2m is gently placed on a flat plate. The space between them is filled with a transparent liquid of refractive index 1.5. The refractive indices of the lens and the flat are 1.4 and 1.6 respectively. The radius of the fifteen dark newtons ring in the reflected light of wavelength λ is found to be √5m.m. Determine the wave length λ (in microns) of the light.Correct answer is '0.25'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The spherical surface of a plane -convex lens of radius of curvature R = 2m is gently placed on a flat plate. The space between them is filled with a transparent liquid of refractive index 1.5. The refractive indices of the lens and the flat are 1.4 and 1.6 respectively. The radius of the fifteen dark newtons ring in the reflected light of wavelength λ is found to be √5m.m. Determine the wave length λ (in microns) of the light.Correct answer is '0.25'. Can you explain this answer?.
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The spherical surface of a plane -convex lens of radius of curvature R = 2m is gently placed on a flat plate. The space between them is filled with a transparent liquid of refractive index 1.5. The refractive indices of the lens and the flat are 1.4 and 1.6 respectively. The radius of the fifteen dark newtons ring in the reflected light of wavelength λ is found to be √5m.m. Determine the wave length λ (in microns) of the light.Correct answer is '0.25'. Can you explain this answer?, a detailed solution for The spherical surface of a plane -convex lens of radius of curvature R = 2m is gently placed on a flat plate. The space between them is filled with a transparent liquid of refractive index 1.5. The refractive indices of the lens and the flat are 1.4 and 1.6 respectively. The radius of the fifteen dark newtons ring in the reflected light of wavelength λ is found to be √5m.m. Determine the wave length λ (in microns) of the light.Correct answer is '0.25'. Can you explain this answer? has been provided alongside types of The spherical surface of a plane -convex lens of radius of curvature R = 2m is gently placed on a flat plate. The space between them is filled with a transparent liquid of refractive index 1.5. The refractive indices of the lens and the flat are 1.4 and 1.6 respectively. The radius of the fifteen dark newtons ring in the reflected light of wavelength λ is found to be √5m.m. Determine the wave length λ (in microns) of the light.Correct answer is '0.25'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice The spherical surface of a plane -convex lens of radius of curvature R = 2m is gently placed on a flat plate. The space between them is filled with a transparent liquid of refractive index 1.5. The refractive indices of the lens and the flat are 1.4 and 1.6 respectively. The radius of the fifteen dark newtons ring in the reflected light of wavelength λ is found to be √5m.m. Determine the wave length λ (in microns) of the light.Correct answer is '0.25'. Can you explain this answer? tests, examples and also practice Physics tests.
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