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A collimated beam of laser light of wavelength 514 nm is normally incident on a smooth glass slab placed in air. Given the refractive indices of glass and air are 1.47 and 1.0 respectively,the percentage of light intensity reflected back is a)0 b) 4.0 c) 3.6 d) 4.2?
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A collimated beam of laser light of wavelength 514 nm is normally inci...
In order to calculate the percentage of light intensity reflected back when a laser beam is incident on a glass slab, we can use the Fresnel equations.
- **Fresnel Equations**: These equations describe the reflection and transmission of light at an interface between two media with different refractive indices.
- **Percentage of Reflected Intensity**: The percentage of light intensity reflected back can be calculated using the formula:
\[ R = \left( \frac{n_1 - n_2}{n_1 + n_2} \right)^2 \times 100\]
- **Given Values**:
- Wavelength of laser light, \( \lambda = 514 \, nm = 514 \times 10^{-9} \, m \)
- Refractive index of glass, \( n_1 = 1.47 \)
- Refractive index of air, \( n_2 = 1.0 \)
- **Calculations**:
\[ \theta_i = 0 \ ( \text{Normal incidence} )\]
\[ \theta_r = 0 \ ( \text{Reflection angle} )\]
\[ \theta_t = 0 \ ( \text{Transmission angle} )\]
Substituting the values into the formula:
\[ R = \left( \frac{1.47 - 1.0}{1.47 + 1.0} \right)^2 \times 100 = \left( \frac{0.47}{2.47} \right)^2 \times 100 = \left( 0.1903 \right)^2 \times 100 = 3.62\%\]
Therefore, the percentage of light intensity reflected back is approximately 3.6%. Hence, the correct answer is **c) 3.6**.
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A collimated beam of laser light of wavelength 514 nm is normally incident on a smooth glass slab placed in air. Given the refractive indices of glass and air are 1.47 and 1.0 respectively,the percentage of light intensity reflected back is a)0 b) 4.0 c) 3.6 d) 4.2?
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A collimated beam of laser light of wavelength 514 nm is normally incident on a smooth glass slab placed in air. Given the refractive indices of glass and air are 1.47 and 1.0 respectively,the percentage of light intensity reflected back is a)0 b) 4.0 c) 3.6 d) 4.2? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about A collimated beam of laser light of wavelength 514 nm is normally incident on a smooth glass slab placed in air. Given the refractive indices of glass and air are 1.47 and 1.0 respectively,the percentage of light intensity reflected back is a)0 b) 4.0 c) 3.6 d) 4.2? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A collimated beam of laser light of wavelength 514 nm is normally incident on a smooth glass slab placed in air. Given the refractive indices of glass and air are 1.47 and 1.0 respectively,the percentage of light intensity reflected back is a)0 b) 4.0 c) 3.6 d) 4.2?.
A collimated beam of laser light of wavelength 514 nm is normally incident on a smooth glass slab placed in air. Given the refractive indices of glass and air are 1.47 and 1.0 respectively,the percentage of light intensity reflected back is a)0 b) 4.0 c) 3.6 d) 4.2? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about A collimated beam of laser light of wavelength 514 nm is normally incident on a smooth glass slab placed in air. Given the refractive indices of glass and air are 1.47 and 1.0 respectively,the percentage of light intensity reflected back is a)0 b) 4.0 c) 3.6 d) 4.2? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A collimated beam of laser light of wavelength 514 nm is normally incident on a smooth glass slab placed in air. Given the refractive indices of glass and air are 1.47 and 1.0 respectively,the percentage of light intensity reflected back is a)0 b) 4.0 c) 3.6 d) 4.2?.
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