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A plain slab of isotropic material of relative permittivity ∈r = 5 is placed normal to a uniform electric field with an electric displacement vector of magnitude 5 Cm2. If the slab occupies a volume of 0.5m3 and is uniformly polarized. Then magnitude of total dipole moment of the slab.
  • a)
    1CM
  • b)
    5CM
  • c)
    2CM
  • d)
    3CM
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A plain slab of isotropic material of relative permittivity∈r = 5...

⇒ 

Here represent the average electric field inside the dielectric. Also the magnitude of total dipole moment of the slab.
 ptotal  = P × volume of the slab
= 4 × 0.5 = 2Cm

The correct answer is: 2CM
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Most Upvoted Answer
A plain slab of isotropic material of relative permittivity∈r = 5...
The relative permittivity of a material is a measure of how easily electric field lines can pass through the material compared to a vacuum. A plain slab of isotropic material means that the material has the same electrical properties in all directions.

The relative permittivity of the material can be denoted as εr. For a plain slab of isotropic material, the relative permittivity is a scalar value that remains constant throughout the material.

When an electric field is applied to the slab, the electric field lines will experience a certain degree of resistance to passing through the material, depending on its relative permittivity. A higher relative permittivity indicates that the material can store more electric charge, while a lower relative permittivity indicates that the material allows electric field lines to pass more easily.

The relative permittivity of a plain slab of isotropic material can be used to calculate various electrical properties, such as the capacitance of a capacitor made from the material or the speed of light when it passes through the material. It is an important parameter in the study of electromagnetism and is often used in the design and analysis of electronic devices and circuits.
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A plain slab of isotropic material of relative permittivity∈r = 5is placed normal to a uniform electric field with an electric displacement vector of magnitude 5Cm2. If the slab occupies a volume of 0.5m3and is uniformly polarized. Then magnitude of total dipole moment of the slab.a)1CMb)5CMc)2CMd)3CMCorrect answer is option 'C'. Can you explain this answer?
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