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A capacitor of capacitance 10µF is charged to a potential of 100V. Now connecting it in parallel with an uncharged capacitor, the resultant potential difference becomes 40volt. The capacitance of this capacitor (in µF) is.
Correct answer is '15'. Can you explain this answer?
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A capacitor of capacitance 10µFis charged to a potential of 100V...
The correct answer is: 15
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A capacitor of capacitance 10µFis charged to a potential of 100V...
A capacitor of capacitance 10 microfarads (10 μF) can store a charge of up to 10 microcoulombs (10 μC) when a voltage of 1 volt is applied across its terminals. The formula to calculate the charge stored in a capacitor is:
Q = C * V
Where:
Q = Charge stored in the capacitor
C = Capacitance of the capacitor
V = Voltage applied across the capacitor
In this case, if the capacitance is 10 μF and the voltage is 1 volt, the charge stored in the capacitor would be:
Q = 10 μF * 1 V
Q = 10 μC
Therefore, the capacitor can store a charge of 10 microcoulombs.
Q = C * V
Where:
Q = Charge stored in the capacitor
C = Capacitance of the capacitor
V = Voltage applied across the capacitor
In this case, if the capacitance is 10 μF and the voltage is 1 volt, the charge stored in the capacitor would be:
Q = 10 μF * 1 V
Q = 10 μC
Therefore, the capacitor can store a charge of 10 microcoulombs.
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A capacitor of capacitance 10µFis charged to a potential of 100V. Now connecting it in parallel with an uncharged capacitor, the resultant potential difference becomes 40volt. The capacitance of this capacitor (inµF) is.Correct answer is '15'. Can you explain this answer?
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