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Two capacitors of 2µF and 3µF are connected in series. The potential at point A is 1000Volt and the outer plate of 3µF capacitor is earthed. The potential at point B is (in Volts).
    Correct answer is '400'. Can you explain this answer?
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    The correct answer is: 400
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    The correct answer is: 400
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    V_B=(2/2+3)*1000=400;
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    Two capacitors of 2µFand 3µFare connected in series. The potential at point A is 1000Voltand the outer plate of 3µFcapacitor is earthed. The potential at point B is (inVolts).Correct answer is '400'. Can you explain this answer?
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    Two capacitors of 2µFand 3µFare connected in series. The potential at point A is 1000Voltand the outer plate of 3µFcapacitor is earthed. The potential at point B is (inVolts).Correct answer is '400'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about Two capacitors of 2µFand 3µFare connected in series. The potential at point A is 1000Voltand the outer plate of 3µFcapacitor is earthed. The potential at point B is (inVolts).Correct answer is '400'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two capacitors of 2µFand 3µFare connected in series. The potential at point A is 1000Voltand the outer plate of 3µFcapacitor is earthed. The potential at point B is (inVolts).Correct answer is '400'. Can you explain this answer?.
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