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A wire under constant tension has a fundamental frequency of 288 hz when its length increase by 10 CM the frequency of vibrations becomes of 256 hz?
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A wire under constant tension has a fundamental frequency of 288 hz wh...


Explanation:

Given Data:
- Fundamental frequency of wire under constant tension: 288 Hz
- Frequency of vibrations after length increase: 256 Hz
- Length increase: 10 cm

Relationship between Frequency and Length:
- The fundamental frequency of a wire is inversely proportional to its length. This means that as the length of the wire increases, the frequency of vibrations decreases.

Calculating the Initial Length:
- Let the initial length of the wire be L.
- Using the given data, we have:
f1 = 1 / 2L * sqrt(T/μ), where f1 = 288 Hz
- Solving for L, we get the initial length of the wire.

Calculating the Final Length:
- After the length increase of 10 cm, the new length of the wire becomes L + 10 cm.
- Using the new length, we can calculate the new frequency of vibrations using the formula:
f2 = 1 / 2(L + 0.1) * sqrt(T/μ), where f2 = 256 Hz

Substituting the Values:
- Substitute the initial and final lengths into the respective frequency formulas to find the initial and final lengths of the wire.

Conclusion:
- By calculating the initial and final lengths of the wire, we can understand how the change in length affects the frequency of vibrations. This relationship helps us analyze the behavior of wires under tension and how different factors influence their vibrations.
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A wire under constant tension has a fundamental frequency of 288 hz when its length increase by 10 CM the frequency of vibrations becomes of 256 hz?
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