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A battery of 6 cells, each of emf 2V and internal resistance 0.5Ω is being charged by a 220V  supplying  an external resistance of 10Ω is series. The potential difference across the battery is :
  • a)
    60 V
  • b)
    120 V 
  • c)
    90 V
  • d)
    180 V
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A battery of 6 cells, each of emf 2Vand internal resistance 0.5Ω...
Total emf of the battery = 12 V
Total internal resistance of the battery = 3Ω
Current through battery (I) = 
Potential difference across battery  = emf of battery + Potential across the battery = 12 + (16 × 3)
= 60 V
The correct answer is: 60 V
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Most Upvoted Answer
A battery of 6 cells, each of emf 2Vand internal resistance 0.5Ω...
In order to solve this problem, we need to use the formula for the total emf and total internal resistance of a battery in series.

The total emf (E_total) of the battery is given by the sum of the emfs of each cell:
E_total = 6 * 2V = 12V

The total internal resistance (R_internal) of the battery is given by the sum of the internal resistances of each cell:
R_internal = 6 * 0.5Ω = 3Ω

Therefore, the battery has a total emf of 12V and a total internal resistance of 3Ω.
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A battery of 6 cells, each of emf 2Vand internal resistance 0.5Ω is being charged by a 220V supplying an external resistance of 10Ω is series. The potential difference across the battery is :a)60Vb)120Vc)90Vd)180VCorrect answer is option 'A'. Can you explain this answer?
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