A satellite close to the earth is in orbit above the equator with the period of rotation of 1.5hours. If it is above a pointPon the equator at some time, it will be abovePagain after time :a)1.5hoursb)24/17hoursif it is rotating from west to eastc)1.6hoursif it is rotating from west to eastd)24/17hoursif it is rotating from east to westCorrect answer is option 'C,D'. Can you explain this answer?

Question

Answer

Let ω₀ = the angular velocity of the earth about its axis.

Let ω = the angular velocity of the satellite

For a satellite rotating from west to east (the same as the earth), the relative angular velocity, ω₁ = ω - ω₀
The period of rotation relative to the earth

For a satellite rotating from east to west (opposite to the earth), the relative angular velocity, ω₂ = ω + ω₀.
The correct answers are: 1.6hours if it is rotating from west to east, 24/17hours if it is rotating from east to west

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