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A block of mass 1kg lies on a horizontal surface in a truck. The coefficient of static friction between the block and the surface is 0.6. If the acceleration of the truck is 5 m/s2, the friction force acting on the block is :
- a)6 N
- b)10 N
- c)5 N
- d)15 N
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
A block of mass 1kglies on a horizontal surface in a truck. The coeffi...
Maximum friction 
Pseudo force = ma = 5N
acceleration due to the applied Pseudo force
So required friction force is only 5N although maximum friction force available is 6N.
The correct answer is: 5 N
Pseudo force = ma = 5N
acceleration due to the applied Pseudo force
So required friction force is only 5N although maximum friction force available is 6N.
The correct answer is: 5 N
Most Upvoted Answer
A block of mass 1kglies on a horizontal surface in a truck. The coeffi...
Friction is the force that opposes the relative motion between two surfaces in contact. In this case, the block and the horizontal surface are in contact, and the friction force prevents the block from sliding on the surface.
Given:
Mass of the block, m = 1 kg
Acceleration of the truck, a = 5 m/s^2
Coefficient of static friction, μ = 0.6
To find: Friction force acting on the block
1. Identifying the Forces:
There are two forces acting on the block:
- The force due to gravity, which can be calculated as the product of mass and acceleration due to gravity (9.8 m/s^2). This force is vertically downward and can be represented as Fg = m * g.
- The friction force, which opposes the motion of the block and acts horizontally. This force is given by Ff = μ * N, where N is the normal force.
2. Calculating the Normal Force:
The normal force is the force exerted by a surface to support the weight of an object resting on it. In this case, the normal force is equal to the force due to gravity acting on the block. Therefore, N = Fg = m * g = 1 kg * 9.8 m/s^2 = 9.8 N.
3. Calculating the Friction Force:
The friction force can be determined using the equation Ff = μ * N. Substituting the values, we get:
Ff = 0.6 * 9.8 N = 5.88 N.
However, it's important to note that this is the maximum static friction force. The actual friction force depends on the force applied to overcome it. In this case, the force applied is the horizontal component of the acceleration of the truck.
4. Comparing with the Applied Force:
The friction force acts in the opposite direction of the applied force. Since the acceleration is in the positive x-direction, the friction force acts in the negative x-direction. Therefore, the magnitude of the friction force is equal to the applied force.
Given that the acceleration of the truck is 5 m/s^2, the friction force acting on the block is 5 N. Hence, the correct answer is option C) 5 N.
Given:
Mass of the block, m = 1 kg
Acceleration of the truck, a = 5 m/s^2
Coefficient of static friction, μ = 0.6
To find: Friction force acting on the block
1. Identifying the Forces:
There are two forces acting on the block:
- The force due to gravity, which can be calculated as the product of mass and acceleration due to gravity (9.8 m/s^2). This force is vertically downward and can be represented as Fg = m * g.
- The friction force, which opposes the motion of the block and acts horizontally. This force is given by Ff = μ * N, where N is the normal force.
2. Calculating the Normal Force:
The normal force is the force exerted by a surface to support the weight of an object resting on it. In this case, the normal force is equal to the force due to gravity acting on the block. Therefore, N = Fg = m * g = 1 kg * 9.8 m/s^2 = 9.8 N.
3. Calculating the Friction Force:
The friction force can be determined using the equation Ff = μ * N. Substituting the values, we get:
Ff = 0.6 * 9.8 N = 5.88 N.
However, it's important to note that this is the maximum static friction force. The actual friction force depends on the force applied to overcome it. In this case, the force applied is the horizontal component of the acceleration of the truck.
4. Comparing with the Applied Force:
The friction force acts in the opposite direction of the applied force. Since the acceleration is in the positive x-direction, the friction force acts in the negative x-direction. Therefore, the magnitude of the friction force is equal to the applied force.
Given that the acceleration of the truck is 5 m/s^2, the friction force acting on the block is 5 N. Hence, the correct answer is option C) 5 N.
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A block of mass 1kglies on a horizontal surface in a truck. The coefficient of static friction between the block and the surface is 0.6. If the acceleration of the truck is 5m/s2, the friction force acting on the block is :a)6 Nb)10 Nc)5 Nd)15 NCorrect answer is option 'C'. Can you explain this answer?
Question Description
A block of mass 1kglies on a horizontal surface in a truck. The coefficient of static friction between the block and the surface is 0.6. If the acceleration of the truck is 5m/s2, the friction force acting on the block is :a)6 Nb)10 Nc)5 Nd)15 NCorrect answer is option 'C'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about A block of mass 1kglies on a horizontal surface in a truck. The coefficient of static friction between the block and the surface is 0.6. If the acceleration of the truck is 5m/s2, the friction force acting on the block is :a)6 Nb)10 Nc)5 Nd)15 NCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A block of mass 1kglies on a horizontal surface in a truck. The coefficient of static friction between the block and the surface is 0.6. If the acceleration of the truck is 5m/s2, the friction force acting on the block is :a)6 Nb)10 Nc)5 Nd)15 NCorrect answer is option 'C'. Can you explain this answer?.
A block of mass 1kglies on a horizontal surface in a truck. The coefficient of static friction between the block and the surface is 0.6. If the acceleration of the truck is 5m/s2, the friction force acting on the block is :a)6 Nb)10 Nc)5 Nd)15 NCorrect answer is option 'C'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about A block of mass 1kglies on a horizontal surface in a truck. The coefficient of static friction between the block and the surface is 0.6. If the acceleration of the truck is 5m/s2, the friction force acting on the block is :a)6 Nb)10 Nc)5 Nd)15 NCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A block of mass 1kglies on a horizontal surface in a truck. The coefficient of static friction between the block and the surface is 0.6. If the acceleration of the truck is 5m/s2, the friction force acting on the block is :a)6 Nb)10 Nc)5 Nd)15 NCorrect answer is option 'C'. Can you explain this answer?.
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A block of mass 1kglies on a horizontal surface in a truck. The coefficient of static friction between the block and the surface is 0.6. If the acceleration of the truck is 5m/s2, the friction force acting on the block is :a)6 Nb)10 Nc)5 Nd)15 NCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for A block of mass 1kglies on a horizontal surface in a truck. The coefficient of static friction between the block and the surface is 0.6. If the acceleration of the truck is 5m/s2, the friction force acting on the block is :a)6 Nb)10 Nc)5 Nd)15 NCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of A block of mass 1kglies on a horizontal surface in a truck. The coefficient of static friction between the block and the surface is 0.6. If the acceleration of the truck is 5m/s2, the friction force acting on the block is :a)6 Nb)10 Nc)5 Nd)15 NCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
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