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(a) Show with labels the splitting of d-orbitals in an octahedral ligand field. Calculate the CFSE of (i) high spin d6 and (ii) low spin d6 metal ions in octahedral field. (b) Schematically represents orbital overlaps in metal carbonyls. Show the correct signs of the lobes
Correct answer is '(a) Octahedral ligand field:(b) Orbital overlaps in metal carbonyls:'. Can you explain this answer?
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(a) Show with labels the splitting of d-orbitals in an octahedral liga...
(a) Octahedral ligand field:

(b) Orbital overlaps in metal carbonyls:
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(a) Show with labels the splitting of d-orbitals in an octahedral liga...
Octahedral Ligand Field:

In an octahedral ligand field, the d-orbitals of a metal ion split into two sets of energy levels. This splitting is a result of the electrostatic interaction between the metal ion and the surrounding ligands. The energy difference between these two sets of levels is known as the crystal field splitting energy (CFSE).

The splitting of d-orbitals in an octahedral ligand field can be shown using labels as follows:

- The three d-orbitals with higher energy are labeled as eg (dx2-y2, dz2, and dxz/dyz).
- The two d-orbitals with lower energy are labeled as t2g (dxy and dxz/dyz).

The eg orbitals are oriented along the axes that point towards the ligands, while the t2g orbitals are oriented between these axes.

Calculation of CFSE:

(i) High Spin d6 Metal Ions:
In a high spin d6 configuration, all six d-electrons occupy the three t2g orbitals before pairing occurs. The CFSE for high spin d6 is calculated using the formula:

CFSE = -0.4 * Δo * n

Where Δo is the crystal field splitting energy and n is the number of unpaired electrons. In the case of high spin d6, n = 4 (since all six electrons are unpaired).

(ii) Low Spin d6 Metal Ions:
In a low spin d6 configuration, three d-electrons occupy the t2g orbitals, and the remaining three electrons pair up in the eg orbitals. The CFSE for low spin d6 is calculated using the formula:

CFSE = -0.6 * Δo * n

Where Δo is the crystal field splitting energy and n is the number of unpaired electrons. In the case of low spin d6, n = 2 (since there are only two unpaired electrons).

Orbital Overlaps in Metal Carbonyls:

In metal carbonyls, the carbon monoxide (CO) ligands act as both sigma (σ) donors and pi (π) acceptors. The sigma-donor interaction involves the overlap of the metal d-orbitals with the antibonding sigma orbital of the CO ligand, while the pi-acceptor interaction involves the overlap of the metal d-orbitals with the filled pi orbitals of the CO ligand.

Schematic representation of orbital overlaps in metal carbonyls can be shown as:

- The sigma-donor interaction involves the overlap of the metal d-orbitals (t2g and eg) with the antibonding sigma orbital of CO.
- The pi-acceptor interaction involves the overlap of the metal d-orbitals (t2g and eg) with the filled pi orbitals of CO.

The correct signs of the lobes in these orbital overlaps are determined by the phase of the wavefunction. For sigma-donor interactions, the lobes with the same phase (positive or negative) overlap, while for pi-acceptor interactions, the lobes with opposite phases overlap.

In summary, the splitting of d-orbitals in an octahedral ligand field can be shown with labels, and the CFSE of high spin and low spin d6 metal ions in an octahedral field can be calculated. Orbital overlaps in metal carbonyls involve sigma-donor and
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(a) Show with labels the splitting of d-orbitals in an octahedral ligand field. Calculate the CFSE of (i) high spin d6 and (ii) low spin d6 metal ions in octahedral field. (b) Schematically represents orbital overlaps in metal carbonyls. Show the correct signs of the lobesCorrect answer is '(a) Octahedral ligand field:(b) Orbital overlaps in metal carbonyls:'. Can you explain this answer?
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(a) Show with labels the splitting of d-orbitals in an octahedral ligand field. Calculate the CFSE of (i) high spin d6 and (ii) low spin d6 metal ions in octahedral field. (b) Schematically represents orbital overlaps in metal carbonyls. Show the correct signs of the lobesCorrect answer is '(a) Octahedral ligand field:(b) Orbital overlaps in metal carbonyls:'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about (a) Show with labels the splitting of d-orbitals in an octahedral ligand field. Calculate the CFSE of (i) high spin d6 and (ii) low spin d6 metal ions in octahedral field. (b) Schematically represents orbital overlaps in metal carbonyls. Show the correct signs of the lobesCorrect answer is '(a) Octahedral ligand field:(b) Orbital overlaps in metal carbonyls:'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for (a) Show with labels the splitting of d-orbitals in an octahedral ligand field. Calculate the CFSE of (i) high spin d6 and (ii) low spin d6 metal ions in octahedral field. (b) Schematically represents orbital overlaps in metal carbonyls. Show the correct signs of the lobesCorrect answer is '(a) Octahedral ligand field:(b) Orbital overlaps in metal carbonyls:'. Can you explain this answer?.
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