If x:y=3:4 , the value of x2y xy2:x3 y3?
Solution:
Given, x:y = 3:4
Let us assume that x = 3a and y = 4a (where a is a constant)
Hence, x2y = (3a)2 (4a) = 36a3
Also, xy2 = (3a) (4a)2 = 48a3
And, x3 y3 = (3a)3 (4a)3 = 1728a6
Therefore, x2y:xy2:x3 y3 = 36a3:48a3:1728a6
On simplifying, we get:
x2y:xy2:x3 y3 = 3:4:144
Hence, the value of x2y:xy2:x3 y3 is 3:4:144.
Explanation:
To solve the given problem, we need to use the concept of ratios and solve for the values of x2y, xy2, and x3 y3.
We assume that x and y are in the ratio of 3:4. By doing so, we can easily represent x and y in terms of a constant, say a. This helps us to find the values of x2y, xy2, and x3 y3.
We use the formulae x2y = x^2 * y, xy2 = x * y^2, and x3 y3 = x^3 * y^3 to find the values of x2y, xy2, and x3 y3 respectively.
Finally, we simplify the ratio by dividing each term by the highest common factor, which is 12a3. This gives us the required ratio of x2y:xy2:x3 y3 as 3:4:144.
If x:y=3:4 , the value of x2y xy2:x3 y3?
LET x=3,y=4
x2y xy2:x3 y3
(9×4 )×(3×16):(27×64)
(36×48):(27×64)
1728:1728
1:1