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The amount of arsenic pentasulphide that can be obtained when 35.5 g arsenic acid is treated with excess H2S in the presence of conc. HCI (assuming 100% conversion) is:a)0.25 moleb)0.50 molec)0.333 moled)0.125 moleCorrect answer is option 'D'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The amount of arsenic pentasulphide that can be obtained when 35.5 g arsenic acid is treated with excess H2S in the presence of conc. HCI (assuming 100% conversion) is:a)0.25 moleb)0.50 molec)0.333 moled)0.125 moleCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The amount of arsenic pentasulphide that can be obtained when 35.5 g arsenic acid is treated with excess H2S in the presence of conc. HCI (assuming 100% conversion) is:a)0.25 moleb)0.50 molec)0.333 moled)0.125 moleCorrect answer is option 'D'. Can you explain this answer?.

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