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It required 0.7 g of hydrocarbon (A) to react completely with 2 g Br. On treatment of A with HBr, it yields monobromo-alkane (B). The same compound B was obtained when A was treated with HBr in the presence of peroxide. Write down the structural formula of A and explain the reactions involved.?
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It required 0.7 g of hydrocarbon (A) to react completely with 2 g Br. ...
Structural Formula of Hydrocarbon A:

The structural formula of hydrocarbon A can be determined by analyzing the amount of Br required to react completely with 0.7 g of A. Since 2 g of Br is required, it can be concluded that A contains two double bonds, as each double bond reacts with one molecule of Br. Therefore, the structural formula of A is:

A = CH2=CH-CH=CH2

Reactions Involved:

1. Reaction of Hydrocarbon A with Br2:

Hydrocarbon A contains two double bonds, which react with Br2 to form a dibromo-alkane. The reaction can be represented as follows:

A + Br2 → Br-CH2-CHBr-CHBr-CH2-Br

2. Reaction of Hydrocarbon A with HBr:

When hydrocarbon A is treated with HBr, it yields monobromo-alkane B. The reaction involves the addition of HBr to one of the double bonds in A. The reaction can be represented as follows:

A + HBr → CH3-CHBr-CH=CH2 + H2

B = CH3-CHBr-CH=CH2

3. Reaction of Hydrocarbon A with HBr in the Presence of Peroxide:

When hydrocarbon A is treated with HBr in the presence of peroxide, it also yields monobromo-alkane B. However, the reaction mechanism is different. In the presence of peroxide, HBr undergoes homolytic cleavage to form Br radicals. These radicals then attack the double bond of A, leading to the formation of B. The reaction can be represented as follows:

A + HBr + peroxide → CH3-CHBr-CH=CH2 + H2O

Conclusion:

Hydrocarbon A is a compound with two double bonds, which can react with Br2 to form a dibromo-alkane. When treated with HBr, it yields monobromo-alkane B. The same compound B is obtained when A is treated with HBr in the presence of peroxide. The reaction mechanism in the presence of peroxide involves the formation of Br radicals, which attack the double bond of A to form B.
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It required 0.7 g of hydrocarbon (A) to react completely with 2 g Br. On treatment of A with HBr, it yields monobromo-alkane (B). The same compound B was obtained when A was treated with HBr in the presence of peroxide. Write down the structural formula of A and explain the reactions involved.?
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It required 0.7 g of hydrocarbon (A) to react completely with 2 g Br. On treatment of A with HBr, it yields monobromo-alkane (B). The same compound B was obtained when A was treated with HBr in the presence of peroxide. Write down the structural formula of A and explain the reactions involved.? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about It required 0.7 g of hydrocarbon (A) to react completely with 2 g Br. On treatment of A with HBr, it yields monobromo-alkane (B). The same compound B was obtained when A was treated with HBr in the presence of peroxide. Write down the structural formula of A and explain the reactions involved.? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for It required 0.7 g of hydrocarbon (A) to react completely with 2 g Br. On treatment of A with HBr, it yields monobromo-alkane (B). The same compound B was obtained when A was treated with HBr in the presence of peroxide. Write down the structural formula of A and explain the reactions involved.?.
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