NEET Exam > NEET Questions > A hydrocarbon (A) is allowed to react with so...
Start Learning for Free
A hydrocarbon (A) is allowed to react with sodium amide and then with ethyl bromide to produce another hydrocarbon (B) which one ozonolysis produces propanoic acid only. The hydrocarbons (A) and (B) are, respectvely,
- a)propyne and 2-pentyne
- b)1-butyne and 3-hexyne
- c)propyne and 3-hexyne
- d)1-butyen and 3-hexene
Correct answer is option 'B'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
A hydrocarbon (A) is allowed to react with sodium amide and then with ...
Most Upvoted Answer
A hydrocarbon (A) is allowed to react with sodium amide and then with ...
Reactants and Products:
- Hydrocarbon (A) reacts with sodium amide and then with ethyl bromide to produce hydrocarbon (B).
- Hydrocarbon (B) undergoes ozonolysis to produce propanoic acid.
Initial Reaction:
- The initial reaction involves the reaction of hydrocarbon (A) with sodium amide.
- Sodium amide is a strong base and is commonly used in organic synthesis to remove acidic hydrogen atoms.
- When hydrocarbon (A) reacts with sodium amide, the acidic hydrogen atoms are removed, resulting in the formation of an alkyne compound.
Reaction with Ethyl Bromide:
- The alkyne compound formed in the previous step reacts with ethyl bromide.
- Ethyl bromide is an alkyl halide that can undergo nucleophilic substitution reactions.
- The alkyne compound acts as a nucleophile and reacts with ethyl bromide, resulting in the addition of an ethyl group to the alkyne.
- This reaction converts the alkyne compound into another hydrocarbon (B).
Ozonolysis:
- Hydrocarbon (B) undergoes ozonolysis, which involves the reaction of the compound with ozone (O3) followed by reductive work-up.
- Ozonolysis breaks the carbon-carbon double or triple bonds in the compound, resulting in the formation of smaller fragments.
- In this case, the ozonolysis of hydrocarbon (B) produces propanoic acid as the only product.
- This suggests that the original hydrocarbon (A) must have contained a double bond that was cleaved during ozonolysis to form propanoic acid.
Identification of Hydrocarbons (A) and (B):
- From the given options, the correct answer is option (B): 1-butyne and 3-hexyne.
- When 1-butyne reacts with sodium amide, the acidic hydrogen atom is removed, resulting in the formation of 1-butyne sodium salt.
- The 1-butyne sodium salt then reacts with ethyl bromide, adding an ethyl group to the alkyne and forming 3-hexyne.
- Upon ozonolysis, 3-hexyne is cleaved to produce smaller fragments, one of which is propanoic acid.
Summary:
- Hydrocarbon (A) is initially converted into an alkyne compound by reacting with sodium amide.
- The alkyne compound reacts with ethyl bromide to form hydrocarbon (B).
- Hydrocarbon (B) undergoes ozonolysis, resulting in the formation of propanoic acid.
- The correct answer is option (B): 1-butyne and 3-hexyne.
- Hydrocarbon (A) reacts with sodium amide and then with ethyl bromide to produce hydrocarbon (B).
- Hydrocarbon (B) undergoes ozonolysis to produce propanoic acid.
Initial Reaction:
- The initial reaction involves the reaction of hydrocarbon (A) with sodium amide.
- Sodium amide is a strong base and is commonly used in organic synthesis to remove acidic hydrogen atoms.
- When hydrocarbon (A) reacts with sodium amide, the acidic hydrogen atoms are removed, resulting in the formation of an alkyne compound.
Reaction with Ethyl Bromide:
- The alkyne compound formed in the previous step reacts with ethyl bromide.
- Ethyl bromide is an alkyl halide that can undergo nucleophilic substitution reactions.
- The alkyne compound acts as a nucleophile and reacts with ethyl bromide, resulting in the addition of an ethyl group to the alkyne.
- This reaction converts the alkyne compound into another hydrocarbon (B).
Ozonolysis:
- Hydrocarbon (B) undergoes ozonolysis, which involves the reaction of the compound with ozone (O3) followed by reductive work-up.
- Ozonolysis breaks the carbon-carbon double or triple bonds in the compound, resulting in the formation of smaller fragments.
- In this case, the ozonolysis of hydrocarbon (B) produces propanoic acid as the only product.
- This suggests that the original hydrocarbon (A) must have contained a double bond that was cleaved during ozonolysis to form propanoic acid.
Identification of Hydrocarbons (A) and (B):
- From the given options, the correct answer is option (B): 1-butyne and 3-hexyne.
- When 1-butyne reacts with sodium amide, the acidic hydrogen atom is removed, resulting in the formation of 1-butyne sodium salt.
- The 1-butyne sodium salt then reacts with ethyl bromide, adding an ethyl group to the alkyne and forming 3-hexyne.
- Upon ozonolysis, 3-hexyne is cleaved to produce smaller fragments, one of which is propanoic acid.
Summary:
- Hydrocarbon (A) is initially converted into an alkyne compound by reacting with sodium amide.
- The alkyne compound reacts with ethyl bromide to form hydrocarbon (B).
- Hydrocarbon (B) undergoes ozonolysis, resulting in the formation of propanoic acid.
- The correct answer is option (B): 1-butyne and 3-hexyne.
Free Test
FREE
| Start Free Test |
Community Answer
A hydrocarbon (A) is allowed to react with sodium amide and then with ...
So cute
Attention NEET Students!
To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.
|
Explore Courses for NEET exam
|
|
Similar NEET Doubts
Top Courses for NEETView all
A hydrocarbon (A) is allowed to react with sodium amide and then with ethyl bromide to produce another hydrocarbon (B) which one ozonolysis produces propanoic acid only. The hydrocarbons (A) and (B) are, respectvely,a)propyne and 2-pentyne b)1-butyne and 3-hexynec)propyne and 3-hexyned)1-butyen and 3-hexeneCorrect answer is option 'B'. Can you explain this answer?
Question Description
A hydrocarbon (A) is allowed to react with sodium amide and then with ethyl bromide to produce another hydrocarbon (B) which one ozonolysis produces propanoic acid only. The hydrocarbons (A) and (B) are, respectvely,a)propyne and 2-pentyne b)1-butyne and 3-hexynec)propyne and 3-hexyned)1-butyen and 3-hexeneCorrect answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A hydrocarbon (A) is allowed to react with sodium amide and then with ethyl bromide to produce another hydrocarbon (B) which one ozonolysis produces propanoic acid only. The hydrocarbons (A) and (B) are, respectvely,a)propyne and 2-pentyne b)1-butyne and 3-hexynec)propyne and 3-hexyned)1-butyen and 3-hexeneCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A hydrocarbon (A) is allowed to react with sodium amide and then with ethyl bromide to produce another hydrocarbon (B) which one ozonolysis produces propanoic acid only. The hydrocarbons (A) and (B) are, respectvely,a)propyne and 2-pentyne b)1-butyne and 3-hexynec)propyne and 3-hexyned)1-butyen and 3-hexeneCorrect answer is option 'B'. Can you explain this answer?.
A hydrocarbon (A) is allowed to react with sodium amide and then with ethyl bromide to produce another hydrocarbon (B) which one ozonolysis produces propanoic acid only. The hydrocarbons (A) and (B) are, respectvely,a)propyne and 2-pentyne b)1-butyne and 3-hexynec)propyne and 3-hexyned)1-butyen and 3-hexeneCorrect answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A hydrocarbon (A) is allowed to react with sodium amide and then with ethyl bromide to produce another hydrocarbon (B) which one ozonolysis produces propanoic acid only. The hydrocarbons (A) and (B) are, respectvely,a)propyne and 2-pentyne b)1-butyne and 3-hexynec)propyne and 3-hexyned)1-butyen and 3-hexeneCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A hydrocarbon (A) is allowed to react with sodium amide and then with ethyl bromide to produce another hydrocarbon (B) which one ozonolysis produces propanoic acid only. The hydrocarbons (A) and (B) are, respectvely,a)propyne and 2-pentyne b)1-butyne and 3-hexynec)propyne and 3-hexyned)1-butyen and 3-hexeneCorrect answer is option 'B'. Can you explain this answer?.
Solutions for A hydrocarbon (A) is allowed to react with sodium amide and then with ethyl bromide to produce another hydrocarbon (B) which one ozonolysis produces propanoic acid only. The hydrocarbons (A) and (B) are, respectvely,a)propyne and 2-pentyne b)1-butyne and 3-hexynec)propyne and 3-hexyned)1-butyen and 3-hexeneCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET.
Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of A hydrocarbon (A) is allowed to react with sodium amide and then with ethyl bromide to produce another hydrocarbon (B) which one ozonolysis produces propanoic acid only. The hydrocarbons (A) and (B) are, respectvely,a)propyne and 2-pentyne b)1-butyne and 3-hexynec)propyne and 3-hexyned)1-butyen and 3-hexeneCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A hydrocarbon (A) is allowed to react with sodium amide and then with ethyl bromide to produce another hydrocarbon (B) which one ozonolysis produces propanoic acid only. The hydrocarbons (A) and (B) are, respectvely,a)propyne and 2-pentyne b)1-butyne and 3-hexynec)propyne and 3-hexyned)1-butyen and 3-hexeneCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for A hydrocarbon (A) is allowed to react with sodium amide and then with ethyl bromide to produce another hydrocarbon (B) which one ozonolysis produces propanoic acid only. The hydrocarbons (A) and (B) are, respectvely,a)propyne and 2-pentyne b)1-butyne and 3-hexynec)propyne and 3-hexyned)1-butyen and 3-hexeneCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of A hydrocarbon (A) is allowed to react with sodium amide and then with ethyl bromide to produce another hydrocarbon (B) which one ozonolysis produces propanoic acid only. The hydrocarbons (A) and (B) are, respectvely,a)propyne and 2-pentyne b)1-butyne and 3-hexynec)propyne and 3-hexyned)1-butyen and 3-hexeneCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A hydrocarbon (A) is allowed to react with sodium amide and then with ethyl bromide to produce another hydrocarbon (B) which one ozonolysis produces propanoic acid only. The hydrocarbons (A) and (B) are, respectvely,a)propyne and 2-pentyne b)1-butyne and 3-hexynec)propyne and 3-hexyned)1-butyen and 3-hexeneCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice NEET tests.
|
|
Explore Courses for NEET exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup