NEET Exam  >  NEET Questions  >  A 27 gm sample of an unknown hydrocarbon was ... Start Learning for Free
A 27 gm sample of an unknown hydrocarbon was burned in excess o2 to form 88gm of co2 and 27gm of h2o what is the possible molecular formula of hydrocarbon? option...1)ch4..2)c2h2..3)c4h3.4)c4h6?
Most Upvoted Answer
A 27 gm sample of an unknown hydrocarbon was burned in excess o2 to fo...
Solution:

Given data:
Mass of unknown hydrocarbon = 27 gm
Mass of CO2 produced = 88 gm
Mass of H2O produced = 27 gm

Let's first find the moles of CO2 and H2O produced in the reaction.

Number of moles of CO2 produced = Mass of CO2 produced/Molar mass of CO2
= 88/44 = 2 moles

Number of moles of H2O produced = Mass of H2O produced/Molar mass of H2O
= 27/18 = 1.5 moles

Now, let's determine the number of moles of carbon and hydrogen in the hydrocarbon.

Number of moles of carbon = Number of moles of CO2 produced
= 2 moles

Number of moles of hydrogen = (Number of moles of H2O produced) x 2
= 1.5 x 2 = 3 moles

Therefore, the empirical formula of the hydrocarbon will be CH2.

Now, let's calculate the molecular formula of the hydrocarbon.

Molecular mass of CH2 = 12 + 2 = 14

Molecular mass of unknown hydrocarbon = Empirical formula mass x n
where n is the number of repeating units

Molecular mass of unknown hydrocarbon = 14 x n

We can find the value of n by dividing the molecular mass of the unknown hydrocarbon by the empirical formula mass.

n = Molecular mass of unknown hydrocarbon/Empirical formula mass
= (27 + 88)/14
= 9

Therefore, the molecular formula of the hydrocarbon is (CH2)9 which can be written as C9H18.

Hence, the possible molecular formula of the hydrocarbon is option 4) C4H6.
Community Answer
A 27 gm sample of an unknown hydrocarbon was burned in excess o2 to fo...
Attention NEET Students!
To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.
Explore Courses for NEET exam

Top Courses for NEET

A 27 gm sample of an unknown hydrocarbon was burned in excess o2 to form 88gm of co2 and 27gm of h2o what is the possible molecular formula of hydrocarbon? option...1)ch4..2)c2h2..3)c4h3.4)c4h6?
Question Description
A 27 gm sample of an unknown hydrocarbon was burned in excess o2 to form 88gm of co2 and 27gm of h2o what is the possible molecular formula of hydrocarbon? option...1)ch4..2)c2h2..3)c4h3.4)c4h6? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A 27 gm sample of an unknown hydrocarbon was burned in excess o2 to form 88gm of co2 and 27gm of h2o what is the possible molecular formula of hydrocarbon? option...1)ch4..2)c2h2..3)c4h3.4)c4h6? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 27 gm sample of an unknown hydrocarbon was burned in excess o2 to form 88gm of co2 and 27gm of h2o what is the possible molecular formula of hydrocarbon? option...1)ch4..2)c2h2..3)c4h3.4)c4h6?.
Solutions for A 27 gm sample of an unknown hydrocarbon was burned in excess o2 to form 88gm of co2 and 27gm of h2o what is the possible molecular formula of hydrocarbon? option...1)ch4..2)c2h2..3)c4h3.4)c4h6? in English & in Hindi are available as part of our courses for NEET. Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of A 27 gm sample of an unknown hydrocarbon was burned in excess o2 to form 88gm of co2 and 27gm of h2o what is the possible molecular formula of hydrocarbon? option...1)ch4..2)c2h2..3)c4h3.4)c4h6? defined & explained in the simplest way possible. Besides giving the explanation of A 27 gm sample of an unknown hydrocarbon was burned in excess o2 to form 88gm of co2 and 27gm of h2o what is the possible molecular formula of hydrocarbon? option...1)ch4..2)c2h2..3)c4h3.4)c4h6?, a detailed solution for A 27 gm sample of an unknown hydrocarbon was burned in excess o2 to form 88gm of co2 and 27gm of h2o what is the possible molecular formula of hydrocarbon? option...1)ch4..2)c2h2..3)c4h3.4)c4h6? has been provided alongside types of A 27 gm sample of an unknown hydrocarbon was burned in excess o2 to form 88gm of co2 and 27gm of h2o what is the possible molecular formula of hydrocarbon? option...1)ch4..2)c2h2..3)c4h3.4)c4h6? theory, EduRev gives you an ample number of questions to practice A 27 gm sample of an unknown hydrocarbon was burned in excess o2 to form 88gm of co2 and 27gm of h2o what is the possible molecular formula of hydrocarbon? option...1)ch4..2)c2h2..3)c4h3.4)c4h6? tests, examples and also practice NEET tests.
Explore Courses for NEET exam

Top Courses for NEET

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev