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A 27 gm sample of an unknown hydrocarbon was burned in excess o2 to form 88gm of co2 and 27gm of h2o what is the possible molecular formula of hydrocarbon? option...1)ch4..2)c2h2..3)c4h3.4)c4h6?
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A 27 gm sample of an unknown hydrocarbon was burned in excess o2 to fo...
Solution:
Given data:
Mass of unknown hydrocarbon = 27 gm
Mass of CO2 produced = 88 gm
Mass of H2O produced = 27 gm
Let's first find the moles of CO2 and H2O produced in the reaction.
Number of moles of CO2 produced = Mass of CO2 produced/Molar mass of CO2
= 88/44 = 2 moles
Number of moles of H2O produced = Mass of H2O produced/Molar mass of H2O
= 27/18 = 1.5 moles
Now, let's determine the number of moles of carbon and hydrogen in the hydrocarbon.
Number of moles of carbon = Number of moles of CO2 produced
= 2 moles
Number of moles of hydrogen = (Number of moles of H2O produced) x 2
= 1.5 x 2 = 3 moles
Therefore, the empirical formula of the hydrocarbon will be CH2.
Now, let's calculate the molecular formula of the hydrocarbon.
Molecular mass of CH2 = 12 + 2 = 14
Molecular mass of unknown hydrocarbon = Empirical formula mass x n
where n is the number of repeating units
Molecular mass of unknown hydrocarbon = 14 x n
We can find the value of n by dividing the molecular mass of the unknown hydrocarbon by the empirical formula mass.
n = Molecular mass of unknown hydrocarbon/Empirical formula mass
= (27 + 88)/14
= 9
Therefore, the molecular formula of the hydrocarbon is (CH2)9 which can be written as C9H18.
Hence, the possible molecular formula of the hydrocarbon is option 4) C4H6.
Given data:
Mass of unknown hydrocarbon = 27 gm
Mass of CO2 produced = 88 gm
Mass of H2O produced = 27 gm
Let's first find the moles of CO2 and H2O produced in the reaction.
Number of moles of CO2 produced = Mass of CO2 produced/Molar mass of CO2
= 88/44 = 2 moles
Number of moles of H2O produced = Mass of H2O produced/Molar mass of H2O
= 27/18 = 1.5 moles
Now, let's determine the number of moles of carbon and hydrogen in the hydrocarbon.
Number of moles of carbon = Number of moles of CO2 produced
= 2 moles
Number of moles of hydrogen = (Number of moles of H2O produced) x 2
= 1.5 x 2 = 3 moles
Therefore, the empirical formula of the hydrocarbon will be CH2.
Now, let's calculate the molecular formula of the hydrocarbon.
Molecular mass of CH2 = 12 + 2 = 14
Molecular mass of unknown hydrocarbon = Empirical formula mass x n
where n is the number of repeating units
Molecular mass of unknown hydrocarbon = 14 x n
We can find the value of n by dividing the molecular mass of the unknown hydrocarbon by the empirical formula mass.
n = Molecular mass of unknown hydrocarbon/Empirical formula mass
= (27 + 88)/14
= 9
Therefore, the molecular formula of the hydrocarbon is (CH2)9 which can be written as C9H18.
Hence, the possible molecular formula of the hydrocarbon is option 4) C4H6.
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A 27 gm sample of an unknown hydrocarbon was burned in excess o2 to fo...
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A 27 gm sample of an unknown hydrocarbon was burned in excess o2 to form 88gm of co2 and 27gm of h2o what is the possible molecular formula of hydrocarbon? option...1)ch4..2)c2h2..3)c4h3.4)c4h6?
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A 27 gm sample of an unknown hydrocarbon was burned in excess o2 to form 88gm of co2 and 27gm of h2o what is the possible molecular formula of hydrocarbon? option...1)ch4..2)c2h2..3)c4h3.4)c4h6? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A 27 gm sample of an unknown hydrocarbon was burned in excess o2 to form 88gm of co2 and 27gm of h2o what is the possible molecular formula of hydrocarbon? option...1)ch4..2)c2h2..3)c4h3.4)c4h6? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 27 gm sample of an unknown hydrocarbon was burned in excess o2 to form 88gm of co2 and 27gm of h2o what is the possible molecular formula of hydrocarbon? option...1)ch4..2)c2h2..3)c4h3.4)c4h6?.
A 27 gm sample of an unknown hydrocarbon was burned in excess o2 to form 88gm of co2 and 27gm of h2o what is the possible molecular formula of hydrocarbon? option...1)ch4..2)c2h2..3)c4h3.4)c4h6? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A 27 gm sample of an unknown hydrocarbon was burned in excess o2 to form 88gm of co2 and 27gm of h2o what is the possible molecular formula of hydrocarbon? option...1)ch4..2)c2h2..3)c4h3.4)c4h6? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 27 gm sample of an unknown hydrocarbon was burned in excess o2 to form 88gm of co2 and 27gm of h2o what is the possible molecular formula of hydrocarbon? option...1)ch4..2)c2h2..3)c4h3.4)c4h6?.
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