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On the first day of a project, 1 woman and 1 child start working. On the second day, 2 more women and 2 more children join the group, on the third day 3 more women and 3 more children join the group, on the fourth day 4 more women and 4 more children join the group, and so on. Thus, the project gets completed in 15 days. Project B which requires thrice the work as Project A has to be completed using only men in 50 days. How many men need to be hired? (Assume the efficiency of 1 man = 1.5 times the efficiency of 1 woman = twice the efficiency of 1 child).
  • a)
    51
  • b)
    55
  • c)
    57
  • d)
    59
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
On the first day of a project, 1 woman and 1 child start working. On t...
1 woman and 1 child works for 15 days 2 women and 2 children work for 14 days 3 women and 3 children work for 13 days.
15 women and 15 children works for 1 day. Total women days = Total children days = (1 x 15) + (2 x 14) + (3 x 13)+ ... + (15 x 1).
Let the efficiency of a child be x per day.
Thus, efficiency of a woman = 1.5x and efficiency of a man = 2x.
Total work in Project A = 680(x + 1.5x) = 1700x. Total work in Project B = 5100x Number of days = 50 Work to be done in each day = 5100x/50 = 102x.
Number of men hired = 102x/2x = 51 Hence, option 1.
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On the first day of a project, 1 woman and 1 child start working. On the second day, 2 more women and 2 more children join the group, on the third day 3 more women and 3 more children join the group, on the fourth day 4 more women and 4 more children join the group, and so on. Thus, the project gets completed in 15 days. Project B which requires thrice the work as Project A has to be completed using only men in 50 days. How many men need to be hired? (Assume the efficiency of 1 man = 1.5 times the efficiency of 1 woman = twice the efficiency of 1 child).a)51b)55c)57d)59Correct answer is option 'A'. Can you explain this answer?
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