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The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 Scm−1. Find its molar conductivity.?
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The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 Scm−1. F...
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The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 Scm−1. F...
Explanation:


Molar conductivity is defined as the conductivity of a solution containing one mole of solute in one litre of solution. It is represented by the symbol Λm. It is also known as the conductivity of a solution at infinite dilution.

Formula:


Molar conductivity (Λm) = Conductivity (κ) / Concentration (c)

Given:


- Concentration of KCl solution (c) = 0.20 M
- Conductivity of KCl solution (κ) = 0.0248 Scm⁻¹

Solution:


Substituting the given values in the above formula, we get:

Λm = κ / c
Λm = 0.0248 Scm⁻¹ / 0.20 M
Λm = 0.124 S cm² mol⁻¹

Therefore, the molar conductivity of the given KCl solution is 0.124 S cm² mol⁻¹.

Explanation:


The molar conductivity of a solution is a measure of its ability to conduct electricity. It is directly proportional to the concentration of ions in the solution. As the concentration of ions increases, the molar conductivity of the solution also increases. The molar conductivity of a solution at infinite dilution is a constant value for a given electrolyte, and it is used to compare the conductivities of different electrolytes.
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The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 Scm−1. Find its molar conductivity.?
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