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An old lady spent one twelfth of her life as a child and one seventh was spent as a teenager. One sixth of her life was spent between the time she became an adult and the time she married. Three years after marriage her daughter was born and the daughter died six years before she died. She lived to be twice as old as her daughter did. How long did the lady’s daughter live?
  • a)
    52 years
  • b)
    45 years
  • c)
    42 years
  • d)
    None of the above
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
An old lady spent one twelfth of her life as a child and one seventh w...
Let the age of the lady at the time of her death be X.
Age spent as child = X/12
Age spent as a teenager = X/7
Age spent between adulthood and marriage = X/6
Age of daughter = X – (X/12 + X/7 + X/6 + 3 + 6) = X - 33X/84 – 9 = 51X/84 – 9
Now, 2(51X/84 – 9) = X
Or 18X/84 = 18
Or X = 84.
Age of daughter = X/2 = 42 years
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An old lady spent one twelfth of her life as a child and one seventh was spent as a teenager. One sixth of her life was spent between the time she became an adult and the time she married. Three years after marriage her daughter was born and the daughter died six years before she died. She lived to be twice as old as her daughter did. How long did the lady’s daughter live?a)52 yearsb)45 yearsc)42 yearsd)None of the aboveCorrect answer is option 'C'. Can you explain this answer?
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