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A thin mid steel wire is loaded by adding loads in equal increments till it breaks. The extensions noted with increasing loads will behave as under
  • a)
    uniform throughout
  • b)
    first increase and then decrease
  • c)
    increase uniformly first and then increase rapidly
  • d)
    increase rapidly first and then uniformly
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A thin mid steel wire is loaded by adding loads in equal increments ti...
At first, the strain is proportional to strain or elongation is proportional to the load giving a straight-line relationship.
A further increase in the load after yield load will cause marked deformation in the whole volume of the metal. The maximum load which the specimen can withstand without failure is called the load at the ultimate strength.
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Most Upvoted Answer
A thin mid steel wire is loaded by adding loads in equal increments ti...
Explanation:

  • When a thin mid steel wire is loaded by adding loads in equal increments till it breaks, the extensions noted with increasing loads will behave as follows.

  • The wire will initially undergo elastic deformation, where the extension will increase uniformly with increasing load.

  • As the load is increased, the deformation will become plastic, and the extension will increase at a faster rate than before.

  • At a certain point, the wire will reach its ultimate strength and undergo necking, where the diameter of the wire decreases at a particular location.

  • This will cause the extension to increase rapidly, and the wire will ultimately fracture.

  • Therefore, the extensions noted with increasing loads will first increase uniformly, then increase uniformly at a faster rate, and finally, increase rapidly before the wire breaks.

  • Hence, the correct option is C, increase uniformly first and then increase rapidly.

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A thin mid steel wire is loaded by adding loads in equal increments till it breaks. The extensions noted with increasing loads will behave as undera)uniform throughoutb)first increase and then decreasec)increase uniformly first and then increase rapidlyd)increase rapidly first and then uniformlyCorrect answer is option 'C'. Can you explain this answer?
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