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There are 4 orange balls, 5 blue balls and 3 white balls are there in a bag. Two balls are selected at random. What is the probability of getting both the balls being blue?
- a)5/33
- b)3/33
- c)3/11
- d)3/5
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
There are 4 orange balls, 5 blue balls and 3 white balls are there in ...
Given information:
- 4 orange balls
- 5 blue balls
- 3 white balls
- Two balls are selected at random
To find: Probability of getting both balls being blue
Solution:
Total number of balls in the bag = 4 + 5 + 3 = 12
Number of ways to select two balls out of 12 = 12C2 = (12*11)/(2*1) = 66
Number of ways to select 2 blue balls out of 5 = 5C2 = (5*4)/(2*1) = 10
Therefore, the probability of getting both balls being blue = (Number of ways to select 2 blue balls out of 5) / (Number of ways to select two balls out of 12) = 10/66 = 5/33
Therefore, the correct option is (a) 5/33.
HTML Code:
- 4 orange balls
- 5 blue balls
- 3 white balls
- Two balls are selected at random
To find: Probability of getting both balls being blue
Solution:
Total number of balls in the bag = 4 + 5 + 3 = 12
Number of ways to select two balls out of 12 = 12C2 = (12*11)/(2*1) = 66
Number of ways to select 2 blue balls out of 5 = 5C2 = (5*4)/(2*1) = 10
Therefore, the probability of getting both balls being blue = (Number of ways to select 2 blue balls out of 5) / (Number of ways to select two balls out of 12) = 10/66 = 5/33
Therefore, the correct option is (a) 5/33.
HTML Code:
Given information:
- 4 orange balls
- 5 blue balls
- 3 white balls
- Two balls are selected at random
To find:
Probability of getting both balls being blue
Solution:
Total number of balls in the bag = 4 + 5 + 3 = 12
Number of ways to select two balls out of 12 = 12C2 = (12*11)/(2*1) = 66
Number of ways to select 2 blue balls out of 5 = 5C2 = (5*4)/(2*1) = 10
Therefore, the probability of getting both balls being blue = (Number of ways to select 2 blue balls out of 5) / (Number of ways to select two balls out of 12) = 10/66 = 5/33
Therefore, the correct option is (a) 5/33.
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Community Answer
There are 4 orange balls, 5 blue balls and 3 white balls are there in ...
P(B)=5c2/12c2
=10/66
hence,p(B)=5/33
=10/66
hence,p(B)=5/33
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There are 4 orange balls, 5 blue balls and 3 white balls are there in a bag. Two balls are selected at random. What is the probability of getting both the balls being blue?a)5/33b)3/33c)3/11d)3/5Correct answer is option 'A'. Can you explain this answer?
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