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Starting from his house Arun moves 5 km to the north east and then 4 km towards south. He now moves 3 km towards east and then moves 8 km towards north to reach his friend’s house. Then his friend’s house is—
- a)5 km north-east of Arun’s house
- b)10 km south-east of Arun’s house
- c)10 km north-east of Arun’s house
- d)10 km north-west of Arun’s house
Correct answer is option 'C'. Can you explain this answer?
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Starting from his house Arun moves 5 km to the north east and then 4 k...
Then Arun’s friend’s house is 5 + 5 = 10 km north from Arun’s house.
Most Upvoted Answer
Starting from his house Arun moves 5 km to the north east and then 4 k...
's house. How far is Arun's friend's house from his own house?
To solve this problem, we can use the Pythagorean theorem to find the distance between Arun's starting point and his friend's house.
First, let's break down Arun's movements:
1. Arun moves 5 km to the northeast. This means he travels 5 km north and 5 km east.
2. Arun then moves 4 km towards the south. This means he cancels out 4 km of his northward movement, leaving him with 1 km north and 5 km east.
3. Arun moves 3 km towards the east. This adds to his eastward movement, giving him a total of 8 km east.
4. Arun finally moves 8 km towards the north, which is added to his existing 1 km northward movement, resulting in a total of 9 km north and 8 km east.
Now, we can use the Pythagorean theorem to find the distance between Arun's starting point and his friend's house:
Distance = √((North)^2 + (East)^2)
Distance = √((9 km)^2 + (8 km)^2)
Distance = √(81 km^2 + 64 km^2)
Distance = √(145 km^2)
Distance ≈ 12.04 km
Therefore, Arun's friend's house is approximately 12.04 km away from his own house.
To solve this problem, we can use the Pythagorean theorem to find the distance between Arun's starting point and his friend's house.
First, let's break down Arun's movements:
1. Arun moves 5 km to the northeast. This means he travels 5 km north and 5 km east.
2. Arun then moves 4 km towards the south. This means he cancels out 4 km of his northward movement, leaving him with 1 km north and 5 km east.
3. Arun moves 3 km towards the east. This adds to his eastward movement, giving him a total of 8 km east.
4. Arun finally moves 8 km towards the north, which is added to his existing 1 km northward movement, resulting in a total of 9 km north and 8 km east.
Now, we can use the Pythagorean theorem to find the distance between Arun's starting point and his friend's house:
Distance = √((North)^2 + (East)^2)
Distance = √((9 km)^2 + (8 km)^2)
Distance = √(81 km^2 + 64 km^2)
Distance = √(145 km^2)
Distance ≈ 12.04 km
Therefore, Arun's friend's house is approximately 12.04 km away from his own house.
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Starting from his house Arun moves 5 km to the north east and then 4 km towards south. He now moves 3 km towards east and then moves 8 km towards north to reach his friend’s house. Then his friend’s house is—a)5 km north-east of Arun’s houseb)10 km south-east of Arun’s housec)10 km north-east of Arun’s housed)10 km north-west of Arun’s houseCorrect answer is option 'C'. Can you explain this answer?
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