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The distance in meters travelled by a particle is related to time in seconds by equation of motion s=5t^.What is the initial velocity of the particle?
Most Upvoted Answer
The distance in meters travelled by a particle is related to time in s...
Initial velocity is 5m/s as the body is moving with uniform velocity so initial velocity is equal to final velocity and equations for motion change in this way with acceleration is zero
s=ut
v=u
v2-u2=0zero
hope it will help
Community Answer
The distance in meters travelled by a particle is related to time in s...
Equation of Motion:
The equation of motion given is s = 5t^2, where s is the distance travelled by the particle in meters and t is the time in seconds.

Understanding the Equation:
The equation represents a quadratic equation, which means it is of the form ax^2 + bx + c = 0. In this case, the equation is s = 5t^2, where a = 5, b = 0, and c = 0.

Interpretation:
The equation shows that the distance travelled by the particle is directly proportional to the square of the time. This means that as time increases, the distance travelled by the particle will increase exponentially.

Initial Velocity:
The initial velocity of the particle can be determined by finding the derivative of the equation of motion with respect to time, t.

Derivative of the Equation:
To find the derivative, we can differentiate the equation s = 5t^2 with respect to t using the power rule of differentiation. The power rule states that if y = x^n, then dy/dx = nx^(n-1).

Differentiating s = 5t^2 with respect to t:
ds/dt = d(5t^2)/dt
ds/dt = 10t

The derivative of the equation of motion is 10t, which represents the rate of change of distance with respect to time. This derivative gives us the velocity of the particle at any given time.

Initial Velocity Calculation:
To find the initial velocity, we need to substitute the initial time, t = 0, into the derivative equation. This is because the initial velocity is the velocity of the particle at the starting point, where time is zero.

Substituting t = 0 into ds/dt = 10t:
ds/dt = 10(0)
ds/dt = 0

The derivative of the equation of motion at t = 0 is 0. This means that the initial velocity of the particle is zero.

Conclusion:
The initial velocity of the particle is zero. This implies that at the starting point, the particle is at rest and has no initial velocity. As time progresses, the particle starts to move and its velocity increases with time according to the equation of motion s = 5t^2.
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The distance in meters travelled by a particle is related to time in seconds by equation of motion s=5t^.What is the initial velocity of the particle?
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