An electrical bulb of resistent 20 ohm and a resistence wire of 4ohm a...
A)Total Resistance in the circuit (Resistance in series)
Rs = R1 + R2
= 20 + 4
= 24 ohms.
b) Current through the circuit (I)
I = V/R
I = 6/24
I = 0.25 A
c) Potential difference (V) across electric bulb
I = V/R1
I = 6/20
I = 0.3 A
d) Potential difference (V) across the resistance wire
I = V/R2
I = 6/4
I = 1.5 A
An electrical bulb of resistent 20 ohm and a resistence wire of 4ohm a...
Total Resistance of the Circuit
To find the total resistance in a series circuit, simply add the individual resistances.
- Resistance of the bulb = 20 ohms
- Resistance of the wire = 4 ohms
Total Resistance (R_total) = 20 ohms + 4 ohms = 24 ohms
Current Through the Circuit
Using Ohm's Law (V = IR), we can calculate the current (I) flowing through the circuit.
- Voltage (V) = 6V
- Total Resistance (R_total) = 24 ohms
Current (I) = V / R_total = 6V / 24 ohms = 0.25 A
Potential Difference Across the Electric Bulb
To find the potential difference across the bulb, use Ohm’s Law again:
- Voltage across the bulb (V_bulb) = I * R_bulb
- I = 0.25 A
- R_bulb = 20 ohms
V_bulb = 0.25 A * 20 ohms = 5V
Potential Difference Across the Resistance Wire
Now, calculate the potential difference across the resistance wire:
- Voltage across the wire (V_wire) = I * R_wire
- R_wire = 4 ohms
V_wire = 0.25 A * 4 ohms = 1V
Resistance of a System of Resistors in Series and Parallel
- Series Connection: Total resistance is the sum of individual resistances. This means R_total = R1 + R2 + R3 + ...
- Parallel Connection: The total resistance decreases and can be calculated using the formula 1/R_total = 1/R1 + 1/R2 + 1/R3 + ...
Understanding these concepts helps in solving various circuit problems efficiently.
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