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An electrical bulb of resistent 20 ohm and a resistence wire of 4ohm are connected in series with a 6V Bettary. draw the diagram and calculate. (a). total resistent of the circuit. (b) current trough the circuit. (c). potential difference across the electric bulb. (d) potential difference across the resistence wire.
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Most Upvoted Answer
An electrical bulb of resistent 20 ohm and a resistence wire of 4ohm a...
A)Total Resistance in the circuit (Resistance in series)
Rs = R1 + R2
= 20 + 4
= 24 ohms.

b) Current through the circuit (I)
I = V/R
I = 6/24
I = 0.25 A

c) Potential difference (V) across electric bulb
I = V/R1
I = 6/20
I = 0.3 A

d) Potential difference (V) across the resistance wire
I = V/R2
I = 6/4
I = 1.5 A
Community Answer
An electrical bulb of resistent 20 ohm and a resistence wire of 4ohm a...
Total Resistance of the Circuit
To find the total resistance in a series circuit, simply add the individual resistances.
- Resistance of the bulb = 20 ohms
- Resistance of the wire = 4 ohms
Total Resistance (R_total) = 20 ohms + 4 ohms = 24 ohms
Current Through the Circuit
Using Ohm's Law (V = IR), we can calculate the current (I) flowing through the circuit.
- Voltage (V) = 6V
- Total Resistance (R_total) = 24 ohms
Current (I) = V / R_total = 6V / 24 ohms = 0.25 A
Potential Difference Across the Electric Bulb
To find the potential difference across the bulb, use Ohm’s Law again:
- Voltage across the bulb (V_bulb) = I * R_bulb
- I = 0.25 A
- R_bulb = 20 ohms
V_bulb = 0.25 A * 20 ohms = 5V
Potential Difference Across the Resistance Wire
Now, calculate the potential difference across the resistance wire:
- Voltage across the wire (V_wire) = I * R_wire
- R_wire = 4 ohms
V_wire = 0.25 A * 4 ohms = 1V
Resistance of a System of Resistors in Series and Parallel
- Series Connection: Total resistance is the sum of individual resistances. This means R_total = R1 + R2 + R3 + ...
- Parallel Connection: The total resistance decreases and can be calculated using the formula 1/R_total = 1/R1 + 1/R2 + 1/R3 + ...
Understanding these concepts helps in solving various circuit problems efficiently.
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An electrical bulb of resistent 20 ohm and a resistence wire of 4ohm are connected in series with a 6V Bettary. draw the diagram and calculate. (a). total resistent of the circuit. (b) current trough the circuit. (c). potential difference across the electric bulb. (d) potential difference across the resistence wire. Related: Resistance of a System of Resistors in Series and Parallel?
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An electrical bulb of resistent 20 ohm and a resistence wire of 4ohm are connected in series with a 6V Bettary. draw the diagram and calculate. (a). total resistent of the circuit. (b) current trough the circuit. (c). potential difference across the electric bulb. (d) potential difference across the resistence wire. Related: Resistance of a System of Resistors in Series and Parallel? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about An electrical bulb of resistent 20 ohm and a resistence wire of 4ohm are connected in series with a 6V Bettary. draw the diagram and calculate. (a). total resistent of the circuit. (b) current trough the circuit. (c). potential difference across the electric bulb. (d) potential difference across the resistence wire. Related: Resistance of a System of Resistors in Series and Parallel? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An electrical bulb of resistent 20 ohm and a resistence wire of 4ohm are connected in series with a 6V Bettary. draw the diagram and calculate. (a). total resistent of the circuit. (b) current trough the circuit. (c). potential difference across the electric bulb. (d) potential difference across the resistence wire. Related: Resistance of a System of Resistors in Series and Parallel?.
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