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A rough vertical board has an acceleration a along the horizontal so that a block of mass M pressing against it does not fall. The coefficient of friction between block and the board is
  • a)
    > a/g
  • b)
    < g/a 
  • c)
    = a/g
  • d)
    > g/a
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
A rough vertical board has an acceleration a along the horizontal so t...
Force on M = Mg
Reaction force = Ma
Force of friction = μR = μ.Ma

Force of friction will balance the weight. So μMa ≥ Mg ; μ ≥ g/a.
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A rough vertical board has an acceleration a along the horizontal so that a block of mass M pressing against it does not fall. The coefficient of friction between block and the board isa)> a/gb)< g/ac)= a/gd)> g/aCorrect answer is option 'D'. Can you explain this answer?
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