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A-4B+ 2C=16, 2A+ 7B-5C=83, then A +B-C=?
Most Upvoted Answer
A-4B+ 2C=16, 2A+ 7B-5C=83, then A +B-C=?
A-4b+2c = 16
2a+7b-5c = 83
—— +
3a +3b-3c = 99

So…..
a + b – c = 33
So the answer is 33
Community Answer
A-4B+ 2C=16, 2A+ 7B-5C=83, then A +B-C=?
Solving for A, B, and C

Using the given equations:


  • A-4B+2C=16

  • 2A+7B-5C=83


Solving for A

Multiply the first equation by 2:


  • 2A-8B+4C=32


Add the second equation to the new equation:


  • 2A-8B+4C+2A+7B-5C=83+32

  • 4A-B=-49

  • A=(49-B)/4


Solving for B

Multiply the first equation by 7:


  • 7A-28B+14C=112


Add the second equation to the new equation:


  • 7A-28B+14C+2A+7B-5C=83+112

  • 9A-21B+9C=195

  • B=(9A+9C-195)/21


Solving for C

Multiply the first equation by 5:


  • 5A-20B+10C=80


Add the second equation to the new equation:


  • 5A-20B+10C+2A+7B-5C=83+80

  • 7A-13B+5C=163

  • C=(163-7A+13B)/5


Calculating A-B+C

Substitute the values of A, B, and C into the expression:


  • A-B+C=[(49-B)/4]-B+[(163-7A+13B)/5]

  • A-B+C=[(49-B)*5-20B+4(163-7A+13B)]/20

  • A-B+C=[245-5B-28A+52B+652-52B]/20

  • A-B+C=(245-28A+652)/20

  • A-B+C=44.85


Therefore, A-B+C is approximately equal to 44.85.
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A-4B+ 2C=16, 2A+ 7B-5C=83, then A +B-C=?
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