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In a series RL circuit R=10ohms ,L=20mH.the circuit current being 10sin314t A,find the total voltage drop (v) across the element R and L.also obtain the phase angle between I and v.?
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In a series RL circuit R=10ohms ,L=20mH.the circuit current being 10si...
Solution:
Calculating the total voltage drop (V) in the circuit:
The total voltage drop across the elements R and L in a series RL circuit can be calculated using the following formula:
V = IR + jIXL
Where,
I = Current flowing through the circuit (10sin314t A)
R = Resistance of the circuit (10 ohms)
L = Inductance of the circuit (20 mH)
Xl = Inductive reactance (2πfL)
f = Frequency of the circuit (314 Hz)
Xl = 2π × 314 × 20 × 10^-3
Xl = 12.56 ohms
Now, substituting the values in the formula, we get:
V = (10sin314t) × 10 + j(10sin314t) × 12.56
V = 100sin314t + j125.6sin314t
Therefore, the total voltage drop across the elements R and L in the circuit is given by:
V = 100sin314t + j125.6sin314t
Calculating the phase angle between current and voltage in the circuit:
The phase angle (φ) between the current and voltage in a series RL circuit can be calculated using the following formula:
φ = tan^-1(Xl/R)
Where,
Xl = Inductive reactance (12.56 ohms)
R = Resistance of the circuit (10 ohms)
Substituting the values in the formula, we get:
φ = tan^-1(12.56/10)
φ = tan^-1(1.256)
φ = 51.34 degrees
Therefore, the phase angle between the current and voltage in the circuit is 51.34 degrees.
Conclusion:
The total voltage drop across the elements R and L in the series RL circuit is V = 100sin314t + j125.6sin314t, and the phase angle between the current and voltage in the circuit is 51.34 degrees.
Calculating the total voltage drop (V) in the circuit:
The total voltage drop across the elements R and L in a series RL circuit can be calculated using the following formula:
V = IR + jIXL
Where,
I = Current flowing through the circuit (10sin314t A)
R = Resistance of the circuit (10 ohms)
L = Inductance of the circuit (20 mH)
Xl = Inductive reactance (2πfL)
f = Frequency of the circuit (314 Hz)
Xl = 2π × 314 × 20 × 10^-3
Xl = 12.56 ohms
Now, substituting the values in the formula, we get:
V = (10sin314t) × 10 + j(10sin314t) × 12.56
V = 100sin314t + j125.6sin314t
Therefore, the total voltage drop across the elements R and L in the circuit is given by:
V = 100sin314t + j125.6sin314t
Calculating the phase angle between current and voltage in the circuit:
The phase angle (φ) between the current and voltage in a series RL circuit can be calculated using the following formula:
φ = tan^-1(Xl/R)
Where,
Xl = Inductive reactance (12.56 ohms)
R = Resistance of the circuit (10 ohms)
Substituting the values in the formula, we get:
φ = tan^-1(12.56/10)
φ = tan^-1(1.256)
φ = 51.34 degrees
Therefore, the phase angle between the current and voltage in the circuit is 51.34 degrees.
Conclusion:
The total voltage drop across the elements R and L in the series RL circuit is V = 100sin314t + j125.6sin314t, and the phase angle between the current and voltage in the circuit is 51.34 degrees.
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In a series RL circuit R=10ohms ,L=20mH.the circuit current being 10sin314t A,find the total voltage drop (v) across the element R and L.also obtain the phase angle between I and v.?
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In a series RL circuit R=10ohms ,L=20mH.the circuit current being 10sin314t A,find the total voltage drop (v) across the element R and L.also obtain the phase angle between I and v.? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about In a series RL circuit R=10ohms ,L=20mH.the circuit current being 10sin314t A,find the total voltage drop (v) across the element R and L.also obtain the phase angle between I and v.? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a series RL circuit R=10ohms ,L=20mH.the circuit current being 10sin314t A,find the total voltage drop (v) across the element R and L.also obtain the phase angle between I and v.?.
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