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A Solution of 8% boric acid is to be kept diluted by adding a 2% boric acid solution to it , the resulting mixture is to be more than 4% but less than 6% boric acid, if we have 640 litres of the 8% solution how many litres of the 2% solution will have to be added?Is the answer 320 is less than x and x is less than 1280, where x denote the liters of 2% boric acid solution is required?
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A Solution of 8% boric acid is to be kept diluted by adding a 2% boric...
Add x liter of 2% boric acid solution. We have to find x when final solution is 4% boric acidBy Equating water content0.98x+.92×640=.96(x+640).02x=25.6x=1280Similarly for 6% boric solution0.98x+.92×640=.94(x+640).04x=12.8x=320
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A Solution of 8% boric acid is to be kept diluted by adding a 2% boric...
Problem:
A 640-liter solution of 8% boric acid needs to be diluted with a 2% boric acid solution. The resulting mixture must have a concentration greater than 4% but less than 6%. How many liters of the 2% solution should be added?
Solution:
To solve this problem, we need to determine the range of possible concentrations for the resulting mixture and find the amount of the 2% solution required to achieve that range.
Range of concentration:
- The resulting mixture should have a concentration greater than 4%, so the minimum concentration is 4%.
- The resulting mixture should have a concentration less than 6%, so the maximum concentration is 6%.
Calculating the minimum and maximum amount of boric acid:
To determine the minimum and maximum amount of boric acid in the resulting mixture, we can use the following formulas:
Minimum amount of boric acid = (total volume of 8% solution) * (minimum concentration)
Maximum amount of boric acid = (total volume of 8% solution) * (maximum concentration)
Substituting the given values:
Minimum amount of boric acid = 640 * 0.04 = 25.6 liters
Maximum amount of boric acid = 640 * 0.06 = 38.4 liters
Calculating the amount of the 2% solution:
The amount of boric acid in the 2% solution can be calculated using the formula:
Amount of boric acid in the 2% solution = (total volume of 2% solution) * (concentration of boric acid)
We need to find the amount of the 2% solution that will provide the required range of boric acid. Let's assume the amount of the 2% solution is x liters.
The amount of boric acid from the 2% solution = x * 0.02
Formulating the equation:
Based on the given conditions, the equation can be written as follows:
Minimum amount of boric acid + Amount of boric acid from the 2% solution = Maximum amount of boric acid
25.6 + (x * 0.02) = 38.4
Solving the equation:
25.6 + 0.02x = 38.4
0.02x = 38.4 - 25.6
0.02x = 12.8
x = 12.8 / 0.02
x = 640
Answer:
The amount of the 2% boric acid solution required is 640 liters. Therefore, the answer should be x = 640, which satisfies the condition 320 < x="" />< 1280.="" />
A 640-liter solution of 8% boric acid needs to be diluted with a 2% boric acid solution. The resulting mixture must have a concentration greater than 4% but less than 6%. How many liters of the 2% solution should be added?
Solution:
To solve this problem, we need to determine the range of possible concentrations for the resulting mixture and find the amount of the 2% solution required to achieve that range.
Range of concentration:
- The resulting mixture should have a concentration greater than 4%, so the minimum concentration is 4%.
- The resulting mixture should have a concentration less than 6%, so the maximum concentration is 6%.
Calculating the minimum and maximum amount of boric acid:
To determine the minimum and maximum amount of boric acid in the resulting mixture, we can use the following formulas:
Minimum amount of boric acid = (total volume of 8% solution) * (minimum concentration)
Maximum amount of boric acid = (total volume of 8% solution) * (maximum concentration)
Substituting the given values:
Minimum amount of boric acid = 640 * 0.04 = 25.6 liters
Maximum amount of boric acid = 640 * 0.06 = 38.4 liters
Calculating the amount of the 2% solution:
The amount of boric acid in the 2% solution can be calculated using the formula:
Amount of boric acid in the 2% solution = (total volume of 2% solution) * (concentration of boric acid)
We need to find the amount of the 2% solution that will provide the required range of boric acid. Let's assume the amount of the 2% solution is x liters.
The amount of boric acid from the 2% solution = x * 0.02
Formulating the equation:
Based on the given conditions, the equation can be written as follows:
Minimum amount of boric acid + Amount of boric acid from the 2% solution = Maximum amount of boric acid
25.6 + (x * 0.02) = 38.4
Solving the equation:
25.6 + 0.02x = 38.4
0.02x = 38.4 - 25.6
0.02x = 12.8
x = 12.8 / 0.02
x = 640
Answer:
The amount of the 2% boric acid solution required is 640 liters. Therefore, the answer should be x = 640, which satisfies the condition 320 < x="" />< 1280.="" />
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A Solution of 8% boric acid is to be kept diluted by adding a 2% boric acid solution to it , the resulting mixture is to be more than 4% but less than 6% boric acid, if we have 640 litres of the 8% solution how many litres of the 2% solution will have to be added?Is the answer 320 is less than x and x is less than 1280, where x denote the liters of 2% boric acid solution is required?
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A Solution of 8% boric acid is to be kept diluted by adding a 2% boric acid solution to it , the resulting mixture is to be more than 4% but less than 6% boric acid, if we have 640 litres of the 8% solution how many litres of the 2% solution will have to be added?Is the answer 320 is less than x and x is less than 1280, where x denote the liters of 2% boric acid solution is required? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about A Solution of 8% boric acid is to be kept diluted by adding a 2% boric acid solution to it , the resulting mixture is to be more than 4% but less than 6% boric acid, if we have 640 litres of the 8% solution how many litres of the 2% solution will have to be added?Is the answer 320 is less than x and x is less than 1280, where x denote the liters of 2% boric acid solution is required? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A Solution of 8% boric acid is to be kept diluted by adding a 2% boric acid solution to it , the resulting mixture is to be more than 4% but less than 6% boric acid, if we have 640 litres of the 8% solution how many litres of the 2% solution will have to be added?Is the answer 320 is less than x and x is less than 1280, where x denote the liters of 2% boric acid solution is required?.
A Solution of 8% boric acid is to be kept diluted by adding a 2% boric acid solution to it , the resulting mixture is to be more than 4% but less than 6% boric acid, if we have 640 litres of the 8% solution how many litres of the 2% solution will have to be added?Is the answer 320 is less than x and x is less than 1280, where x denote the liters of 2% boric acid solution is required? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about A Solution of 8% boric acid is to be kept diluted by adding a 2% boric acid solution to it , the resulting mixture is to be more than 4% but less than 6% boric acid, if we have 640 litres of the 8% solution how many litres of the 2% solution will have to be added?Is the answer 320 is less than x and x is less than 1280, where x denote the liters of 2% boric acid solution is required? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A Solution of 8% boric acid is to be kept diluted by adding a 2% boric acid solution to it , the resulting mixture is to be more than 4% but less than 6% boric acid, if we have 640 litres of the 8% solution how many litres of the 2% solution will have to be added?Is the answer 320 is less than x and x is less than 1280, where x denote the liters of 2% boric acid solution is required?.
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