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If z1 = 2 + i, z2 = 1 + 3i, then Re ( z1 - z2) =
- a)ι
- b)1
- c)2 ι
- d)2
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
If z1= 2 + i, z2= 1 + 3i, then Re ( z1- z2) =a)ιb)1c)2 ιd)2C...
The numbers in the questions are not very clear.
z1 = 2 + i
z2 = 1+3i
z1 – z2 = (2 – 1) + i (1 – 3)
= 1 – 2i
z1 = 2 + i
z2 = 1+3i
z1 – z2 = (2 – 1) + i (1 – 3)
= 1 – 2i
Most Upvoted Answer
If z1= 2 + i, z2= 1 + 3i, then Re ( z1- z2) =a)ιb)1c)2 ιd)2C...
1
To find Re(z1 - z2), we first need to subtract z2 from z1:
z1 - z2 = (2i) - (1 + 3i) = 1 - i
Now, to find the real part of this complex number, we simply take the real component, which is 1. Therefore, Re(z1 - z2) = 1.
To find Re(z1 - z2), we first need to subtract z2 from z1:
z1 - z2 = (2i) - (1 + 3i) = 1 - i
Now, to find the real part of this complex number, we simply take the real component, which is 1. Therefore, Re(z1 - z2) = 1.
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If z1= 2 + i, z2= 1 + 3i, then Re ( z1- z2) =a)ιb)1c)2 ιd)2C...
Z1 - Z2 = 2 + i - 1 - 3i = = 1 - 2i
comparing from a+ ib where a = real part and b = imaginary part So,
a = 1 = Real part of ( Z1 - Z2)
Thus option (B) is the correct answer
comparing from a+ ib where a = real part and b = imaginary part So,
a = 1 = Real part of ( Z1 - Z2)
Thus option (B) is the correct answer
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If z1= 2 + i, z2= 1 + 3i, then Re ( z1- z2) =a)ιb)1c)2 ιd)2Correct answer is option 'B'. Can you explain this answer?
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