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A dice has 3 faces each bearing ‘ 2 ‘ and three faces each bearing ‘ 6 ‘. It is rolled once. The probability of showing up ‘a six ‘ is
  • a)
    1/2
  • b)
    1
  • c)
    1/6
  • d)
    none of these
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A dice has 3 faces each bearing ‘ 2 ‘ and three faces each...
S = {2, 2, 2, 6, 6, 6}
n(S) = 6
n(6) = 3 
P(showing up a 6) = n(6)/n(S) = 3/6 = 1/2
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A dice has 3 faces each bearing ‘ 2 ‘ and three faces each bearing ‘ 6 ‘. It is rolled once. The probability of showing up ‘a six ‘ isa)1/2b)1c)1/6d)none of theseCorrect answer is option 'A'. Can you explain this answer?
Question Description
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