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If two bulbs A(25W-220V) & B(100W-220V) are connected in series with the supply of 330 volt, which bulb will fuse?
- a)A
- b)B
- c)Both
- d)none
Correct answer is option 'A'. Can you explain this answer?
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If two bulbs A(25W-220V) & B(100W-220V) are connected in series wi...
Analysis:
The bulbs are connected in series with a supply of 330 volts. The total voltage drop across the two bulbs will be 330 volts. Each bulb will have a voltage drop across it based on its power rating and the total voltage.
Calculations:
- Voltage drop across bulb A:
\( V_A = \frac{P_A}{P_A + P_B} \times V_{total} \)
\( V_A = \frac{25}{25 + 100} \times 330 \)
\( V_A = \frac{25}{125} \times 330 \)
\( V_A = \frac{1}{5} \times 330 \)
\( V_A = 66 V \)
- Voltage drop across bulb B:
\( V_B = \frac{P_B}{P_A + P_B} \times V_{total} \)
\( V_B = \frac{100}{25 + 100} \times 330 \)
\( V_B = \frac{100}{125} \times 330 \)
\( V_B = \frac{4}{5} \times 330 \)
\( V_B = 264 V \)
Conclusion:
- The voltage drop across bulb A is 66 volts, which is less than the rated voltage of 220 volts. Thus, bulb A will not fuse.
- The voltage drop across bulb B is 264 volts, which is more than the rated voltage of 220 volts. Thus, bulb B will fuse in this setup.
Therefore, the correct answer is option A - Bulb B will fuse.
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If two bulbs A(25W-220V) & B(100W-220V) are connected in series with the supply of 330 volt, which bulb will fuse?a)Ab)Bc)Bothd)noneCorrect answer is option 'A'. Can you explain this answer?
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