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A ray of light goes from a medium of refractive index μ1 to a medium of refractive index μ2. Theangle of incidence is i and the angle of refraction is r. Then, sin i/sin r is equal to
  • a)
    μ1
  • b)
    μ2
  • c)
    μ1/μ2
  • d)
    μ2/μ1
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
A ray of light goes from a medium of refractive index μ1 to a mediu...
Refractive index, also called index of refraction, measure  of the bending of a ray of light when passing from one medium into another. As per Snell's law and the given information ;
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A ray of light goes from a medium of refractive index μ1 to a mediu...
1.5 to another medium of refractive index 1.2. The angle of incidence is 30 degrees. What is the angle of refraction?

Using Snell's Law:

n1*sin(theta1) = n2*sin(theta2)

n1 = 1.5 (refractive index of first medium)
theta1 = 30 degrees (angle of incidence)
n2 = 1.2 (refractive index of second medium)
theta2 = ?

Rearranging the equation and solving for theta2:

sin(theta2) = (n1/n2)*sin(theta1)

sin(theta2) = (1.5/1.2)*sin(30)

sin(theta2) = 0.75

theta2 = sin^-1(0.75)

theta2 = 48.59 degrees

Therefore, the angle of refraction is 48.59 degrees.
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Community Answer
A ray of light goes from a medium of refractive index μ1 to a mediu...
Sin i/ sin r = u2/u1 where u2 and u1 is refractive index of medium 2 and 1. When medium one is air then value of refractive index u1= 1.
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A ray of light goes from a medium of refractive index μ1 to a medium of refractive index μ2. Theangle of incidence is i and the angle of refraction is r. Then, sin i/sin r is equal toa)μ1b)μ2c)μ1/μ2d)μ2/μ1Correct answer is option 'D'. Can you explain this answer?
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