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If the root of the equation x•2 - 8x m = 0 exceeds the other by 4 then the value of 4 is?
Most Upvoted Answer
If the root of the equation x•2 - 8x m = 0 exceeds the other by 4 th...
Explanation:

Given equation is x² - 8x = m.

Let the roots of the equation be α and β.

α + β = 8 (Sum of the roots of the quadratic equation is -b/a which is -(-8)/1 = 8)

αβ = m (Product of the roots of the quadratic equation is c/a which is 0/m = 0)

α - β = 4 (Given the root of the equation x² - 8x = m exceeds the other by 4)

Solution:

We need to find the value of 4.

Let's substitute the value of α and β in the equation α - β = 4

α - β = 4

(α + β) - 2β = 4 (Substituting α + β = 8)

8 - 2β = 4

2β = 4

β = 2

Now, we can find the value of α by substituting β in the equation α + β = 8

α + 2 = 8

α = 6

The roots of the equation are α = 6 and β = 2.

Let's find the value of m using the equation αβ = m

m = αβ

m = 6 × 2

m = 12

Therefore, the value of 4 is 4.
Community Answer
If the root of the equation x•2 - 8x m = 0 exceeds the other by 4 th...
Let the roots are
x and x+4 
Sum of roots = x+(x+4) =-(-8/1)
                             2x+4 = 8
                              2x = 4
                               x=2
Now,
x^2-8x+m=0
Put x = 2
(2)^2-8(2)+m=0
4-16+m=0
-12+m=0
m=12
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If the root of the equation x•2 - 8x m = 0 exceeds the other by 4 then the value of 4 is?
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