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 If the root of the equation x2-8x+m=0 exceeds the other by 4 then the value of m is
  • a)
    m=10
  • b)
    m=11
  • c)
    m=9
  • d)
    m=12
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
If the root of the equation x2-8x+m=0 exceeds the other by 4 then the ...
Given equation: x² - 8x + m = 0

Let α and β be the roots of the equation, hence we have:

α + β = 8 ...(1)
α - β = 4 ...(2)

Adding equations (1) and (2), we get:

2α = 12

α = 6

Substituting the value of α in equation (1), we get:

β = 2

Therefore, the roots of the equation are α = 6 and β = 2.

We know that the difference between the roots of the equation is given by:

α - β = 6 - 2 = 4

Therefore, we have:

m = αβ

m = 6 × 2

m = 12

Hence, the value of m is 12, which is option (d).
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If the root of the equation x2-8x+m=0 exceeds the other by 4 then the value of m isa)m=10b)m=11c)m=9d)m=12Correct answer is option 'D'. Can you explain this answer?
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