If 50% of the 2:3 solution of milk and water is replaced with water, t...
Let the quantity of milk and water be 40 and 60 respectively
After removing 50% of solution
Quantity of milk = 20 and quantity of water = 30
Therefore, the concentration of the solution is reduced from 40 to 20 i.e., reduced by 50%
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If 50% of the 2:3 solution of milk and water is replaced with water, t...
Question Analysis:
We are given a 2:3 solution of milk and water. We need to find the change in concentration of the solution when 50% of it is replaced with water.
Given:
- Initial solution ratio of milk to water = 2:3
- 50% of the solution is replaced with water
Calculating the Initial Concentration:
To find the initial concentration, we need to determine the ratio of milk to the total solution.
Let the initial quantity of the solution be 5 units (2 units of milk and 3 units of water). The total quantity is divided into two parts: milk and water.
- Quantity of milk = 2/5 * 5 = 2 units
- Quantity of water = 3/5 * 5 = 3 units
Therefore, the initial concentration of the solution is 2:3 (milk:water).
Calculating the Final Concentration:
When 50% of the solution is replaced with water, half of the milk is also replaced with water.
Let's consider the initial quantity of the solution as 10 units for easier calculation. So, 50% of 10 units is 5 units.
- Quantity of milk in the replaced portion = 2/5 * 5 = 2 units
- Quantity of water in the replaced portion = 3/5 * 5 = 3 units
After replacing 5 units of the solution, the new quantity becomes 5 units (3 units of water and 2 units of milk).
Therefore, the final concentration of the solution is 2:3 (milk:water).
Calculating the Change in Concentration:
To find the change in concentration, we need to compare the initial and final concentrations.
Initial concentration = 2:3
Final concentration = 2:3
We can see that the initial and final concentrations are the same. Hence, there is no change in concentration.
Answer:
The concentration of the solution is not reduced by any percentage. Therefore, the correct answer is option 'C' - 50%.
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