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The coefficient of mutual inductance, when magnetic flux changes by 2 X 10-2 Wb and current changes by 0.01 A is

  • a)
    2 H

  • b)
    4 H

  • c)
    3 H

  • d)
    8 H

Correct answer is option 'A'. Can you explain this answer?
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The coefficient of mutual inductance, when magnetic flux changes by 2 ...
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The coefficient of mutual inductance, when magnetic flux changes by 2 ...
Given:
Change in magnetic flux = 2 x 10^-2 Wb
Change in current = 0.01 A

To find: Coefficient of mutual inductance (M)

Formula:

M = ΔΦ/ΔI

Where,
ΔΦ = Change in magnetic flux
ΔI = Change in current

Calculation:

M = ΔΦ/ΔI
M = (2 x 10^-2 Wb)/(0.01 A)
M = 2 H

Therefore, the coefficient of mutual inductance is 2 H.
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The coefficient of mutual inductance, when magnetic flux changes by 2 ...
Given:
Change in magnetic flux, ΔΦ = 2 × 10⁻² Wb
Change in current, ΔI = 0.01 A

Formula used:
Coefficient of mutual inductance, M = ΔΦ/ΔI

Calculation:
Substituting the given values in the formula, we get
M = ΔΦ/ΔI = (2 × 10⁻² Wb)/(0.01 A) = 2 H

Therefore, the coefficient of mutual inductance is 2 H.
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The coefficient of mutual inductance, when magnetic flux changes by 2 X 10-2 Wb and current changes by 0.01 A isa)2 Hb)4 Hc)3 Hd)8 HCorrect answer is option 'A'. Can you explain this answer?
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