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Solve by elimination method 1/7x 1/6y=3 1/2x-1/3y=5?
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Solve by elimination method 1/7x 1/6y=3 1/2x-1/3y=5?
Solving by Elimination Method
Given equations:
1/7x + 1/6y = 3 ....(1)
1/2x - 1/3y = 5 ....(2)
Step 1: Multiply the equations
Multiply equation (1) by 6 and equation (2) by 21 to eliminate y.
6(1/7x + 1/6y = 3) => 6/7x + y/6 = 18 ....(3)
21(1/2x - 1/3y = 5) => 10.5x - 7y = 105 ....(4)
Step 2: Add the equations
Adding equations (3) and (4) eliminates y.
6/7x + y/6 = 18
10.5x - 7y = 105
6/7x + 10.5x = 18 + 105
7.5x = 123
x = 16.4
Step 3: Substitute x value in one of the original equations
Substitute x = 16.4 in equation (1) to find y.
1/7(16.4) + 1/6y = 3
2.3428 + 0.1667y = 3
0.1667y = 0.6572
y = 3.9432
Step 4: Check the solution
Substitute x = 16.4 and y = 3.9432 in both equations to check if the solution is correct.
1/7(16.4) + 1/6(3.9432) = 3
1.997 + 0.6572 = 3
3 = 3
1/2(16.4) - 1/3(3.9432) = 5
8.2 - 1.3144 = 5
5 = 5
Therefore, the solution is x = 16.4 and y = 3.9432.
Community Answer
Solve by elimination method 1/7x 1/6y=3 1/2x-1/3y=5?
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