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Find the sum of first 12 term of the Ap 5,8,11,14. .?
Most Upvoted Answer
Find the sum of first 12 term of the Ap 5,8,11,14. .?
A=5,
a2=8,
d=a2-a1=8-5=3,
n=12,
a12=a+11d=5+11(3)=5+33=38,
s12=n/2(a+l),
=12/2(5+38),
=6(43)=258
Community Answer
Find the sum of first 12 term of the Ap 5,8,11,14. .?
Sum of First 12 Terms of an AP


An arithmetic progression (AP) is a sequence of numbers in which the difference between any two consecutive terms is constant. To find the sum of the first 12 terms of the AP 5, 8, 11, 14, we can use the formula:


Sum of first n terms of an AP = n/2[2a + (n-1)d]


Where:


  • n is the number of terms we want to add

  • a is the first term of the AP

  • d is the common difference between the terms



Identifying the Values


In this problem, we have:


  • n = 12 (since we want to add the first 12 terms)

  • a = 5 (since 5 is the first term of the AP)

  • d = 3 (since the difference between any two consecutive terms is 3)



Applying the Formula


Substituting the values we have into the formula, we get:


Sum of first 12 terms of 5, 8, 11, 14 = 12/2[2(5) + (12-1)(3)]

= 6[10 + 33]

= 6 x 43

= 258


Answer


Therefore, the sum of the first 12 terms of the AP 5, 8, 11, 14 is 258.
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Find the sum of first 12 term of the Ap 5,8,11,14. .?
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