Given:
Students participating in all the clubs are 3, i.e. m = 3 ...(1)
Number of students only in cricket is 4 times the number of students in both football and hockey clubs,
i.e. p = 4(m + c) ...(2)
Ratio of the number of students only in football club to the number of students only in hockey club is 3 : 2.
q/r = 3/2 ...(3)
Ratio of the number of students only in hockey club to the number of students only in cricket club is 1 : 2.
r/p = 1/2 ...(4)
The number of students in both cricket and football clubs is the same as the number of students only in the hockey club.
a + m = r ...(5)
The number of students in both cricket and hockey clubs are 10 and the number of students in football and hockey clubs is twice that number.
b + m = 10 ...(6)
m + c = 20 ...(7)
Putting the value of m from (1) in (6) and (7), gives:
b = 7
c = 17
Putting value of m + c from (7) in (2), gives:
p = 4(20)
p = 80
Putting 'p' in (4),
r = 40
And, putting 'r' in (3) gives q = 60.
Further, putting value of r in (5),
a + 3 = 40
a = 37
Total number of students = p + q + r + a + b + c + m
= 80 + 60 + 40 + 37 + 7 + 17 + 3
= 244
75% of the students in the college are not in any of these clubs, this means that 25% attend the club, i.e. 0.25(x) = 244,
where x = total no of students in college.
x = 976
The number of students in football and cricket only is 37.