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The system shown in the figure is in equilibrium, where A and B are isomeric liquids and form an ideal solution at T.K. standard vapour pressure of A and B are PA° and PB° respectively at TK. We collect the vapour of A and B in two container of volume V, first container is maintained at 2TK and second container is maintained at 3TK.2At thetemperature greater than TK, both A and B exist in only gaseous form. Total vapour pressure of the system at TK is given as PT = PA°XA+ PB°XBWhere XA and XB are the mole fraction of A and B in liquid a mixture.In container (1) We assume that collected gases behave ideally at 2TK and there can take place isomerisation reaction in which A converted into B by first order kinetics Reaction is given asIn Container (II) At the given temperature 3T/2, A and B are ideal in nature and non mixing in nature. A small pin hole is madecontainer. We can determine the initial rate of effusion of both gases in vacuum by the expressionWhere P = pressure difference between system and surrounding K = positive constant M = Molecular weight of the gas.Q.If partial vapour pressure of A is twice that of partial vapour pressure of B and total V.P. is equal to 2T at T = 50 K and V = B.21 lit, then number of mole of A and B in vapour phase is :a)8/3,4/3b)3, 1c)2, 2d)1, 3Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The system shown in the figure is in equilibrium, where A and B are isomeric liquids and form an ideal solution at T.K. standard vapour pressure of A and B are PA° and PB° respectively at TK. We collect the vapour of A and B in two container of volume V, first container is maintained at 2TK and second container is maintained at 3TK.2At thetemperature greater than TK, both A and B exist in only gaseous form. Total vapour pressure of the system at TK is given as PT = PA°XA+ PB°XBWhere XA and XB are the mole fraction of A and B in liquid a mixture.In container (1) We assume that collected gases behave ideally at 2TK and there can take place isomerisation reaction in which A converted into B by first order kinetics Reaction is given asIn Container (II) At the given temperature 3T/2, A and B are ideal in nature and non mixing in nature. A small pin hole is madecontainer. We can determine the initial rate of effusion of both gases in vacuum by the expressionWhere P = pressure difference between system and surrounding K = positive constant M = Molecular weight of the gas.Q.If partial vapour pressure of A is twice that of partial vapour pressure of B and total V.P. is equal to 2T at T = 50 K and V = B.21 lit, then number of mole of A and B in vapour phase is :a)8/3,4/3b)3, 1c)2, 2d)1, 3Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The system shown in the figure is in equilibrium, where A and B are isomeric liquids and form an ideal solution at T.K. standard vapour pressure of A and B are PA° and PB° respectively at TK. We collect the vapour of A and B in two container of volume V, first container is maintained at 2TK and second container is maintained at 3TK.2At thetemperature greater than TK, both A and B exist in only gaseous form. Total vapour pressure of the system at TK is given as PT = PA°XA+ PB°XBWhere XA and XB are the mole fraction of A and B in liquid a mixture.In container (1) We assume that collected gases behave ideally at 2TK and there can take place isomerisation reaction in which A converted into B by first order kinetics Reaction is given asIn Container (II) At the given temperature 3T/2, A and B are ideal in nature and non mixing in nature. A small pin hole is madecontainer. We can determine the initial rate of effusion of both gases in vacuum by the expressionWhere P = pressure difference between system and surrounding K = positive constant M = Molecular weight of the gas.Q.If partial vapour pressure of A is twice that of partial vapour pressure of B and total V.P. is equal to 2T at T = 50 K and V = B.21 lit, then number of mole of A and B in vapour phase is :a)8/3,4/3b)3, 1c)2, 2d)1, 3Correct answer is option 'A'. Can you explain this answer?.

Solutions for The system shown in the figure is in equilibrium, where A and B are isomeric liquids and form an ideal solution at T.K. standard vapour pressure of A and B are PA° and PB° respectively at TK. We collect the vapour of A and B in two container of volume V, first container is maintained at 2TK and second container is maintained at 3TK.2At thetemperature greater than TK, both A and B exist in only gaseous form. Total vapour pressure of the system at TK is given as PT = PA°XA+ PB°XBWhere XA and XB are the mole fraction of A and B in liquid a mixture.In container (1) We assume that collected gases behave ideally at 2TK and there can take place isomerisation reaction in which A converted into B by first order kinetics Reaction is given asIn Container (II) At the given temperature 3T/2, A and B are ideal in nature and non mixing in nature. A small pin hole is madecontainer. We can determine the initial rate of effusion of both gases in vacuum by the expressionWhere P = pressure difference between system and surrounding K = positive constant M = Molecular weight of the gas.Q.If partial vapour pressure of A is twice that of partial vapour pressure of B and total V.P. is equal to 2T at T = 50 K and V = B.21 lit, then number of mole of A and B in vapour phase is :a)8/3,4/3b)3, 1c)2, 2d)1, 3Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of The system shown in the figure is in equilibrium, where A and B are isomeric liquids and form an ideal solution at T.K. standard vapour pressure of A and B are PA° and PB° respectively at TK. We collect the vapour of A and B in two container of volume V, first container is maintained at 2TK and second container is maintained at 3TK.2At thetemperature greater than TK, both A and B exist in only gaseous form. Total vapour pressure of the system at TK is given as PT = PA°XA+ PB°XBWhere XA and XB are the mole fraction of A and B in liquid a mixture.In container (1) We assume that collected gases behave ideally at 2TK and there can take place isomerisation reaction in which A converted into B by first order kinetics Reaction is given asIn Container (II) At the given temperature 3T/2, A and B are ideal in nature and non mixing in nature. A small pin hole is madecontainer. We can determine the initial rate of effusion of both gases in vacuum by the expressionWhere P = pressure difference between system and surrounding K = positive constant M = Molecular weight of the gas.Q.If partial vapour pressure of A is twice that of partial vapour pressure of B and total V.P. is equal to 2T at T = 50 K and V = B.21 lit, then number of mole of A and B in vapour phase is :a)8/3,4/3b)3, 1c)2, 2d)1, 3Correct answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of The system shown in the figure is in equilibrium, where A and B are isomeric liquids and form an ideal solution at T.K. standard vapour pressure of A and B are PA° and PB° respectively at TK. We collect the vapour of A and B in two container of volume V, first container is maintained at 2TK and second container is maintained at 3TK.2At thetemperature greater than TK, both A and B exist in only gaseous form. Total vapour pressure of the system at TK is given as PT = PA°XA+ PB°XBWhere XA and XB are the mole fraction of A and B in liquid a mixture.In container (1) We assume that collected gases behave ideally at 2TK and there can take place isomerisation reaction in which A converted into B by first order kinetics Reaction is given asIn Container (II) At the given temperature 3T/2, A and B are ideal in nature and non mixing in nature. A small pin hole is madecontainer. We can determine the initial rate of effusion of both gases in vacuum by the expressionWhere P = pressure difference between system and surrounding K = positive constant M = Molecular weight of the gas.Q.If partial vapour pressure of A is twice that of partial vapour pressure of B and total V.P. is equal to 2T at T = 50 K and V = B.21 lit, then number of mole of A and B in vapour phase is :a)8/3,4/3b)3, 1c)2, 2d)1, 3Correct answer is option 'A'. Can you explain this answer?, a detailed solution for The system shown in the figure is in equilibrium, where A and B are isomeric liquids and form an ideal solution at T.K. standard vapour pressure of A and B are PA° and PB° respectively at TK. We collect the vapour of A and B in two container of volume V, first container is maintained at 2TK and second container is maintained at 3TK.2At thetemperature greater than TK, both A and B exist in only gaseous form. Total vapour pressure of the system at TK is given as PT = PA°XA+ PB°XBWhere XA and XB are the mole fraction of A and B in liquid a mixture.In container (1) We assume that collected gases behave ideally at 2TK and there can take place isomerisation reaction in which A converted into B by first order kinetics Reaction is given asIn Container (II) At the given temperature 3T/2, A and B are ideal in nature and non mixing in nature. A small pin hole is madecontainer. We can determine the initial rate of effusion of both gases in vacuum by the expressionWhere P = pressure difference between system and surrounding K = positive constant M = Molecular weight of the gas.Q.If partial vapour pressure of A is twice that of partial vapour pressure of B and total V.P. is equal to 2T at T = 50 K and V = B.21 lit, then number of mole of A and B in vapour phase is :a)8/3,4/3b)3, 1c)2, 2d)1, 3Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of The system shown in the figure is in equilibrium, where A and B are isomeric liquids and form an ideal solution at T.K. standard vapour pressure of A and B are PA° and PB° respectively at TK. We collect the vapour of A and B in two container of volume V, first container is maintained at 2TK and second container is maintained at 3TK.2At thetemperature greater than TK, both A and B exist in only gaseous form. Total vapour pressure of the system at TK is given as PT = PA°XA+ PB°XBWhere XA and XB are the mole fraction of A and B in liquid a mixture.In container (1) We assume that collected gases behave ideally at 2TK and there can take place isomerisation reaction in which A converted into B by first order kinetics Reaction is given asIn Container (II) At the given temperature 3T/2, A and B are ideal in nature and non mixing in nature. A small pin hole is madecontainer. We can determine the initial rate of effusion of both gases in vacuum by the expressionWhere P = pressure difference between system and surrounding K = positive constant M = Molecular weight of the gas.Q.If partial vapour pressure of A is twice that of partial vapour pressure of B and total V.P. is equal to 2T at T = 50 K and V = B.21 lit, then number of mole of A and B in vapour phase is :a)8/3,4/3b)3, 1c)2, 2d)1, 3Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice The system shown in the figure is in equilibrium, where A and B are isomeric liquids and form an ideal solution at T.K. standard vapour pressure of A and B are PA° and PB° respectively at TK. We collect the vapour of A and B in two container of volume V, first container is maintained at 2TK and second container is maintained at 3TK.2At thetemperature greater than TK, both A and B exist in only gaseous form. Total vapour pressure of the system at TK is given as PT = PA°XA+ PB°XBWhere XA and XB are the mole fraction of A and B in liquid a mixture.In container (1) We assume that collected gases behave ideally at 2TK and there can take place isomerisation reaction in which A converted into B by first order kinetics Reaction is given asIn Container (II) At the given temperature 3T/2, A and B are ideal in nature and non mixing in nature. A small pin hole is madecontainer. We can determine the initial rate of effusion of both gases in vacuum by the expressionWhere P = pressure difference between system and surrounding K = positive constant M = Molecular weight of the gas.Q.If partial vapour pressure of A is twice that of partial vapour pressure of B and total V.P. is equal to 2T at T = 50 K and V = B.21 lit, then number of mole of A and B in vapour phase is :a)8/3,4/3b)3, 1c)2, 2d)1, 3Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice JEE tests.