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Two oxides of a metal contain 27.6% and 30% of oxygen respectively.If the formula of the first compound is M3O4, then find the formula of second compound?
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Two oxides of a metal contain 27.6% and 30% of oxygen respectively.If ...
Given that, formula of first oxide=M3​O4​
Let mass of the metal = x
% of metal in M3​O4​ =3x+643x​×100
But  as given % age =(100−27.6)=72.4%
so, 3x+643x​×100 = 72.4
or x=56.
In 2nd oxide,
Given, oxygen = 30%, So metal = 70%
So, the ratio is
M:O=5670​:1630​
⟹1.25:1.875
⟹2:3
So, 2nd oxide is M2​O3​
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Two oxides of a metal contain 27.6% and 30% of oxygen respectively.If ...
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Two oxides of a metal contain 27.6% and 30% of oxygen respectively.If the formula of the first compound is M3O4, then find the formula of second compound?
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