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Half-life of a zero order reaction is 250sec. t75% ,t100% of the reaction respectively in sec. are?
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Half-life of a zero order reaction is 250sec. t75% ,t100% of the react...
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Half-life of a zero order reaction is 250sec. t75% ,t100% of the react...
Explanation:

  • A zero order reaction follows the rate equation of the form: Rate = k[A]^0 = k

  • The rate of the reaction is constant and independent of the concentration of the reactant.

  • The half-life of a zero order reaction is given by the relation: t1/2 = [A]0/2k.

  • Where [A]0 is the initial concentration of the reactant and k is the rate constant.

  • Given, t1/2 = 250 sec.

  • Therefore, [A]0/2k = 250 sec.

  • From this equation, we can find the value of k.

  • k = [A]0/500 sec.



t75% of the reaction:

  • t75% means the time required for the reaction to reach 75% completion.

  • Let's assume that the initial concentration of the reactant is [A]0.

  • After 75% completion, the concentration of the reactant will be [A] = 0.25[A]0.

  • The time required for the reaction to reach this concentration can be calculated using the rate equation:

  • [A] = -kt + [A]0

  • t = ([A]0 - [A])/k

  • Substituting the values, we get:

  • t75% = ([A]0 - 0.25[A]0)/k = 0.75[A]0/k = 0.75*500 sec = 375 sec.



t100% of the reaction:

  • t100% means the time required for the reaction to reach 100% completion.

  • After 100% completion, the concentration of the reactant will be zero.

  • The time required for the reaction to reach this concentration can be calculated using the rate equation:

  • [A] = -kt + [A]0

  • t = [A]0/k

  • Substituting the values, we get:

  • t100% = [A]0/k = 500 sec.

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Half-life of a zero order reaction is 250sec. t75% ,t100% of the reaction respectively in sec. are?
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