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Places A and B are 100 KM apart on a highway one car starts from A and another from B at the same time with the past travel in the same direction at different speeds 3 5 hours if they travel towards Each Other they meet in an hour what are the speeds of the two cars ?
Most Upvoted Answer
Places A and B are 100 KM apart on a highway one car starts from A and...
Explanation:
Let the speed of the car starting from point A be x km/h and the speed of the car starting from point B be y km/h.

When they travel in the same direction:
Distance = 100 km
Time taken by car starting from A = 3 hours
Time taken by car starting from B = 5 hours

Let's calculate the distance traveled by both the cars in 1 hour:
Distance traveled by the car starting from A in 1 hour = x km/h
Distance traveled by the car starting from B in 1 hour = y km/h

Distance traveled by the car starting from A in 3 hours = 3x km
Distance traveled by the car starting from B in 5 hours = 5y km

As both the cars are traveling in the same direction, the relative speed of the cars = (y - x) km/h
Relative speed of the cars = Distance traveled by the car starting from A in 3 hours + Distance traveled by the car starting from B in 5 hours
(y - x) km/h = 3x + 5y
y - x = (3/5)x + y
x/5 = 2y/5
x = 2y

When they travel towards each other:
Distance = 100 km
Time taken = 1 hour
Relative speed of the cars = (x + y) km/h

Distance traveled by both the cars = Relative speed × Time taken
100 = (x + y) × 1
x + y = 100

We have two equations:
x = 2y
x + y = 100

Solving these equations, we get:
x = 40 km/h
y = 20 km/h

Therefore, the speed of the car starting from point A is 40 km/h and the speed of the car starting from point B is 20 km/h.
Community Answer
Places A and B are 100 KM apart on a highway one car starts from A and...
ANSWER
Let the speed of car at A be x kmph
and the speed of car at B be y kmph

when the car travel in same direction Relative Speed is x−y
Dist=100km
t=5 hours
∴ Dist =S×T
100=(x−y)5
x−y=20⟶(I)

when car travel in opp direction Relative Speed is x+y
Dist=100km
t=1 hours
Dist=ST
100=(x+y)1
x+y=100⟶(II)

Solving (I) & (II)
x−y=20
x+y=100


2x=120
x=60km/h
y=40km/h

Speed of the car at A =60 km/h
Speed of the car at B=40 km/h
The difference of speeds is 60−40=20
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Places A and B are 100 KM apart on a highway one car starts from A and another from B at the same time with the past travel in the same direction at different speeds 3 5 hours if they travel towards Each Other they meet in an hour what are the speeds of the two cars ?
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