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When H₂O₂ is added to acidified solution of dichromate ion, then deep blue colour is produced due to the formation of
  • a)
    Cr₂O₃
  • b)
    CrO₄2
  • c)
    CrO₃
  • d)
    CrO₅
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
When HO is added to acidified solution of dichromate ion, then deep bl...
Explanation:

When HO (Hydroxyl ion) is added to an acidified solution of dichromate ion, a deep blue color is produced due to the formation of CrO (Chromate ion).

Reaction:

The reaction involved in this process is the reduction of dichromate ion (Cr2O7^2-) to chromate ion (CrO4^2-) by hydroxyl ion (HO^-).

Cr2O7^2- + 14H^+ + 6e^- → 2CrO4^2- + 7H2O

Explanation of the reaction:

1. The dichromate ion (Cr2O7^2-) is a strong oxidizing agent, while the hydroxyl ion (HO^-) is a strong reducing agent.

2. In an acidified solution, the dichromate ion accepts electrons from the hydroxyl ion and gets reduced to chromate ion.

3. The hydroxyl ion loses electrons and gets oxidized to water.

4. The deep blue color is due to the formation of chromate ion (CrO4^2-), which has a blue color.

Key Points:

- The addition of hydroxyl ion (HO^-) to an acidified solution of dichromate ion (Cr2O7^2-) results in the reduction of dichromate ion to chromate ion.

- The deep blue color observed is due to the formation of chromate ion (CrO4^2-).

- The reaction can be represented by the balanced chemical equation: Cr2O7^2- + 14H^+ + 6e^- → 2CrO4^2- + 7H2O.
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When HO is added to acidified solution of dichromate ion, then deep blue colour is produced due to the formation ofa)CrOb)CrO2c)CrOd)CrOCorrect answer is option 'D'. Can you explain this answer?
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