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A compound contain 69.5% oxygen and 30.5% nitrogen and its molecular weight is 92. The formula of the compound is
- a)N2O
- b)NO2
- c)N2O4
- d)N2O5
Correct answer is option 'C'. Can you explain this answer?
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A compound contain 69.5% oxygen and 30.5% nitrogen and its molecular w...
Formula of a Compound containing Oxygen and Nitrogen
Given:
Percentage of oxygen = 69.5%
Percentage of nitrogen = 30.5%
Molecular weight = 92
To find:
Formula of the compound
Solution:
Step 1:
Calculate the number of moles of oxygen and nitrogen present in the compound.
Let us assume that we have 100 grams of the compound.
Number of moles of oxygen = (69.5/100) x (100/16) = 4.34 moles
Number of moles of nitrogen = (30.5/100) x (100/14) = 2.18 moles
Step 2:
Calculate the empirical formula of the compound.
The empirical formula is the simplest whole number ratio of atoms present in a compound.
To calculate the empirical formula, we divide the number of moles of each element by its smallest value.
Here, the smallest value is 2.18.
Empirical formula = (4.34/2.18)O(N/2.18)
Simplifying this, we get the empirical formula as N2O4.
Step 3:
Calculate the molecular formula of the compound.
The molecular formula is a multiple of the empirical formula.
Molecular weight of N2O4 = (2 x 14) + (4 x 16) = 92
Hence, the molecular formula of the compound is N2O4.
Therefore, the correct option is C) N2O4.
Given:
Percentage of oxygen = 69.5%
Percentage of nitrogen = 30.5%
Molecular weight = 92
To find:
Formula of the compound
Solution:
Step 1:
Calculate the number of moles of oxygen and nitrogen present in the compound.
Let us assume that we have 100 grams of the compound.
Number of moles of oxygen = (69.5/100) x (100/16) = 4.34 moles
Number of moles of nitrogen = (30.5/100) x (100/14) = 2.18 moles
Step 2:
Calculate the empirical formula of the compound.
The empirical formula is the simplest whole number ratio of atoms present in a compound.
To calculate the empirical formula, we divide the number of moles of each element by its smallest value.
Here, the smallest value is 2.18.
Empirical formula = (4.34/2.18)O(N/2.18)
Simplifying this, we get the empirical formula as N2O4.
Step 3:
Calculate the molecular formula of the compound.
The molecular formula is a multiple of the empirical formula.
Molecular weight of N2O4 = (2 x 14) + (4 x 16) = 92
Hence, the molecular formula of the compound is N2O4.
Therefore, the correct option is C) N2O4.
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A compound contain 69.5% oxygen and 30.5% nitrogen and its molecular weight is 92. The formula of the compound isa)N2Ob)NO2c)N2O4d)N2O5Correct answer is option 'C'. Can you explain this answer?
Question Description
A compound contain 69.5% oxygen and 30.5% nitrogen and its molecular weight is 92. The formula of the compound isa)N2Ob)NO2c)N2O4d)N2O5Correct answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A compound contain 69.5% oxygen and 30.5% nitrogen and its molecular weight is 92. The formula of the compound isa)N2Ob)NO2c)N2O4d)N2O5Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A compound contain 69.5% oxygen and 30.5% nitrogen and its molecular weight is 92. The formula of the compound isa)N2Ob)NO2c)N2O4d)N2O5Correct answer is option 'C'. Can you explain this answer?.
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