Analysis of Compound

To determine the formula of the compound, we need to analyze the given information about the mass of iodine and oxygen present in the compound.

Given Information:
- Mass of iodine: 254 grams
- Mass of oxygen: 80 grams

Step 1: Convert mass to moles
To compare the number of atoms of iodine and oxygen, we need to convert the mass of each element into moles using their respective molar masses. The molar mass of iodine is 126.90 g/mol, and the molar mass of oxygen is 16.00 g/mol.

- Moles of iodine = Mass of iodine / Molar mass of iodine
= 254 g / 126.90 g/mol
≈ 2 moles

- Moles of oxygen = Mass of oxygen / Molar mass of oxygen
= 80 g / 16.00 g/mol
= 5 moles

Step 2: Determine the ratio of moles
The ratio of moles of iodine to oxygen in the compound will provide insights into its formula. Dividing the number of moles of each element by the smallest number of moles will give the simplest whole number ratio.

- Ratio of iodine to oxygen = Moles of iodine / Moles of oxygen
= 2 moles / 5 moles
= 0.4

Step 3: Convert ratio to whole numbers
To convert the ratio obtained in Step 2 into whole numbers, we multiply by a factor that will give us the simplest whole number ratio. In this case, multiplying by 2 will give us a ratio of 2 iodine atoms to 5 oxygen atoms.

- Simplified ratio = 0.4 * 2 (multiply by 2 to get whole numbers)
= 0.8 iodine : 2 oxygen
= 4 iodine : 10 oxygen
= 2 iodine : 5 oxygen

Step 4: Determine the formula
The ratio of 2 iodine atoms to 5 oxygen atoms suggests that the formula of the compound contains two iodine atoms for every five oxygen atoms. Therefore, the formula of the compound is I2O5.

Conclusion:
Based on the analysis, the compound contains 254 grams of iodine and 80 grams of oxygen, and its formula is I2O5.

I(2)O(5)